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2 years ago

What are other ways you can use wind energy to create electricity?

Chemistry

2 answers:

Phantasy [73]2 years ago

8 0

You can use a fan on the wire. That's one way.

Anettt [7]2 years ago

5 0

Ooh! i like the fan on the wire! i would listen to the person above me:)

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An atom that has 13 protons and 15 neutrons is element

ololo11 [35]

Answer:

you are correct

Explanation:

i double checked u are correct :D

4 0

2 years ago

Which statement about anabolism is true?

skelet666 [1.2K]

Answer:

i would say B? Im sorry if im wrong

Explanation:

i think that because Catabolic reactions release energy, while anabolic reactions use up energy. Anabolism is the opposite of catabolism.

8 0

2 years ago

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In which of the following does nitrogen have the lowest oxidation state?

Leokris [45]

Nh4cl (the oxidation number of N=-3) so it would be the right answer

3 0

10 months ago

Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI

NeTakaya

Answer :

AgI should precipitate first.

The concentration of $Ag^+$ when CuI just begins to precipitate is, $6.64\times 10^{-7}M$

Percent of $Ag^+$ remains is, 0.0076 %

Explanation :

$K_{sp}$ for CuI is $1\times 10^{-12}$

$K_{sp}$ for AgI is $8.3\times 10^{-17}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

$CuI\rightleftharpoons Cu^++I^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Cu^+][I^-]$

$1\times 10^{-12}=0.0079\times [I^-]$

$[I^-]=1.25\times 10^{-10}M$

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

$AgI\rightleftharpoons Ag^++I^-$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ag^+][I^-]$

$8.3\times 10^{-17}=[Ag^+]\times 1.25\times 10^{-10}M$

$[Ag^+]=6.64\times 10^{-7}M$

Now we have to calculate the percent of $Ag^+$ remains in solution at this point.

Percent of $Ag^+$ remains = $\frac{6.64\times 10^{-7}}{0.0087}\times 100$

Percent of $Ag^+$ remains = 0.0076 %

8 0

3 years ago

How is electromagnetic energy fromthe microwave transformed into heat energy

zysi [14]

Answer:

First, the microwaves transmit kinetic energy to the water molecules of the food, heating the water molecules. Only, those that are not very deep into the food.

Second, the hot water molecules transmit heat by conduction to the other parts of the food.

Explanation:

1) Microwaves are a form of electromagnetic radiation. The same as any wave, they carry energy.

2) The wave length of microwaves are in the range of 0.001 mm to 1 m (shorter than radio waves and longer than infrared)

3) The microwaves of an oven, used to heat food, have a wave length aroun 12 cm.

4) The microwaves transmit energy to the water molecules in the food, by increasing the kinetic energy of water molecules. As result, the water molecules get hotter. Microwaves only penetrate about 1 cm inside the food (a potato for example) and from that the heat is transferred by conduction to the inner parts of the food.

6 0

3 years ago

Read 2 more answers