Answer:
56.7°
Step-by-step explanation:
A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter side of the rectangle to the nearest tenth of a degree?
We solve this question using the Trigonometric function of Sine
From the question, we are told that:
A rectangle is 5.1 cm wide
and each diagonal is 9.3 cm long.
Since we have a diagonal, this means the shape is transformed to a triangle.
The width of the rectangle = Adjacent side of a triangle = 5.1cm
The diagonal of the rectangle = Hypotenuse = 9.3cm
Hence,
cosθ = Adjacent/Hypotenuse
cosθ = 5.1/9.3
cosθ = 0.5483870968
θ = arccos(0.5483870968)
θ = 56.743568714°
Approximately = 56.7°
The measure of the angle is 56.7°
Answer:
Step-by-step explanation:
For a:
ax = c - by
a = (c - by)/x
For x:
ax = c - by
x = (c - by)/a
For b:
by = c - ax
b = (c - ax)/y
For y:
by = c - ax
y = (c - ax)/b
Add 3y and 4y: 7y=56
Divide by 7: y=8
Answer:
15.9
Step-by-step explanation:
so -9.7 is 9.7 jumps form 0 and same for 6.2 is 6.2 jumps from 0
9.7 + 6.2 = 15.9
the distance between -9.7 and 6.2 is 15.9
