The coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4) is 
Explanation :
the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)
Apply section formula to find coordinates of point Q
Ratio m:n is 2:3 and point R is (x1,y1) , point S is (x2,y2)
Substitute all the values inside the formula
The coordinates of point Q is
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I think the answer would be 2.05 because 6.15/3 is 2.05
1) The function is
3(x + 2)³ - 32) The
end behaviour is the
limits when x approaches +/- infinity.3) Since the polynomial is of
odd degree you can predict that
the ends head off in opposite direction. The limits confirm that.
4) The limit when x approaches negative infinity is negative infinity, then
the left end of the function heads off downward (toward - ∞).
5) The limit when x approaches positive infinity is positivie infinity, then
the right end of the function heads off upward (toward + ∞).
6) To graph the function it is important to determine:
- x-intercepts
- y-intercepts
- critical points: local maxima, local minima, and inflection points.
7)
x-intercepts ⇒ y = 0⇒ <span>
3(x + 2)³ - 3 = 0 ⇒ (x + 2)³ - 1 = 0
</span>
<span>⇒ (x + 2)³ = -1 ⇒ x + 2 = 1 ⇒
x = - 1</span>
8)
y-intercepts ⇒ x = 0y = <span>3(x + 2)³ - 3 =
3(0 + 2)³ - 3 = 0 - 3×8 - 3 = 24 - 3 =
21</span><span>
</span><span>
</span><span>9)
Critical points ⇒ first derivative = 0</span><span>
</span><span>
</span><span>i) dy / dx = 9(x + 2)² = 0
</span><span>
</span><span>
</span><span>⇒ x + 2 = 0 ⇒
x = - 2</span><span>
</span><span>
</span><span>ii)
second derivative: to determine where x = - 2 is a local maximum, a local minimum, or an inflection point.
</span><span>
</span><span>
</span><span>
y'' = 18 (x + 2); x = - 2 ⇒ y'' = 0 ⇒ inflection point.</span><span>
</span><span>
</span><span>Then the function does not have local minimum nor maximum, but an
inflection point at x = -2.</span><span>
</span><span>
</span><span>Using all that information you can
graph the function, and I
attache the figure with the graph.
</span>
Answer:
9
Step-by-step explanation:
To find the area of a triangle where you know the x and y coordinates of the three vertices, you'll need to use the coordinate geometry formula: area = the absolute value of Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By) divided by 2. Ax and Ay are the x and y coordinates for the vertex of A. The same applies for the x and y notations of the B and C vertices.
Fill in the numbers for each corresponding letter combination within the formula.
Fill in your formula like this: 0(8-10) + 3(0-0) + 9(0-8).
Subtract the numbers within the parentheses.
0 from 8 = 8, 0 from 0 = 0 and 8 from 10 = 2.
Multiply that result by the number to the left of the parentheses.
0 by 8 = 0, 3 by 0 = 0 and 9 by 2 = 18.
Add the three products together.
0 + 0 + 18 = 18
Divide the sum of the three products by 2.
18 ÷ 2 = 9
