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zhannawk [14.2K]
3 years ago
7

Please help me!!!!!!!!!!

Mathematics
1 answer:
Elenna [48]3 years ago
5 0

The answer is d.

Remember open circle means that it cannot be equal to that value while closed circle means that it can be.

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A supermarket offers a delivery service. If a customer pays $9 per month, each delivery costs just $2. Write an equation that sh
Rzqust [24]

The linear function that models the total cost for x deliveries is:

y(x) = 2x + 9

-------------------

A linear function has the following format:

y = mx + b

In which

  • m is the slope, that is, the rate of change.
  • b is the y-intercept, that is, the value of y when x = 0.

In this problem:

  • Fixed cost of $9 per month, b = 9.
  • Cost of $2 for each delivery, thus m = 2.

The function for the <u>total cost for x deliveries is:</u>

y(x) = 2x + 9

A similar problem is given at brainly.com/question/16270359

4 0
3 years ago
Which of the following equations represents a horizontal line? (A y=x) (B x=5) (C y=-12) (D y=-x+1)
boyakko [2]
The answer is (C y=-12) Due to the fact that the line would be on the y axis, below 12, straight across. 
3 0
3 years ago
Let F (x; y) = xy2i + x2y j. Evaluate ∫F.ds (from c to [infinity]) where C is the upper half of the circle of radius 1 centered
77julia77 [94]

Answer:

The integral \int F \bullets ds is 0.

Step-by-step explanation:

A parameterization of curve C can be:

X (t) = cost 0 <= t <= pi

Y (t) = sint 0 <= t <= pi

r (t) = costi + sintj

r '(t) = -sinti + costj

Fds = [-costsin^3t + sintcos^3t] dt

The integral \int F \bullets ds is given by:

\int _0^{\pi }\left[-costsin^3t + sintcos^3t dt\right]dt

= \int _0^{\pi }-sin ^3tcostdt + \int _0^{\pi }sintcos^3tdt = 0

4 0
3 years ago
There are 15 boys and 21 girls in a class. Write the simplified ratio of boys to students in three different ways.
gladu [14]
There are 6 less boys then girls
there are 6 more girls then boys
there are 15 boys compared to 21 girls
4 0
3 years ago
Read 2 more answers
How do you solve my problem​
antiseptic1488 [7]

Where is your problem

3 0
3 years ago
Read 2 more answers
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