All categories

3 years ago

A varies jointly as b and c. Find when b = 7 and c = 9, if the constant is the variation is 3.

Mathematics

2 answers:

bogdanovich [222]3 years ago

7 0

189 would be correct!

Harman [31]3 years ago

3 0

Answer:

Option A is correct

Value of A is, 189

Step-by-step explanation:

Joint variation states:

A varies jointly as b and c.

⇒ $A \propto b$ and $A \propto c$

⇒ $A \propto bc$

then the equation is in the form of:

$A = k \cdot bc$

where, k is the constant of variation.

As per the statement:

A varies jointly as b and c.

⇒ $A = k \cdot bc$ ....[1]

To find A .

Substitute the given values b = 7 , c = 9 and k = 3 in [1]

then;

$A = 3 \cdot 7 \cdot 9 = 21 \cdot 9 = 189$

Therefore, the value of A is, 189

You might be interested in

the area of a rectangular pool is given by the trinomial to 2y^2+y - 3 what are the possible dimensions of a pool. use factoring

gtnhenbr [62]

2y² + y - 3

(2y+3)(y-1)

2y(y-1) + 3(y-1)
2y² - 2y + 3y - 3
2y² + y - 3

2y + 3 = 0
2y = -3
y = -3/2
y = -1 1/2

y - 1 = 0
y = 1

2y² + y - 3 = 0
2(-3/2)² + (-3/2) - 3 = 0
2(9/4) - 3/2 - 3 = 0
18/4 - 3/2 - 3 = 0
18/4 - (3/2 * 2/2) - 3(4/4) = 0
18/4 - 6/4 - 12/4 = 0
(18 - 6 - 12)/4 = 0
(18 -18)/4 = 0
0/4 = 0
0 = 0

4 0

4 years ago

What is the solution to 3.2x = 6.4?

jeyben [28]

A. X = 2
what you do is divide each side by the coefficient of x (3.2) to get rid of it on the left, and simplify the right: 2.

6 0

4 years ago

Please help me out with this so I can keep my kitten.

notka56 [123]

Answer:

$y = \frac{32}{3}$

Step-by-step explanation:

Firstly, move over the negative 3/4 fraction (don't forget to swap the operation i.e subtract to add):

$\frac{y}{8} = \frac{7}{12} + \frac{3}{4}$

Now, to add the two fractions, simply multiply the numerator and denominator by 3:

$\frac{3*3}{4*3} = \frac{9}{12}$

Now add this to the other fraction:

$\frac{9}{12} + \frac{7}{12} = \frac{16}{12}$

This can be simplified down by dividing both the numerator and denominator by 4:

$\frac{4}{3}$

Which now simplifies the original equation to:

$\frac{y}{8} = \frac{4}{3}$

Remove the y out of the fraction:

$\frac{1}{8}y = \frac{4}{3}$

Now multiply both sides by 8:

$(\frac{1}{8}y) * 8 = (\frac{4}{3}) * 8$

$y = \frac{4*8}{3}$

$y = \frac{32}{3}$

Hope this helps!

5 0

3 years ago

Read 2 more answers

Say a hacker has a list of n distinct password candidates, only one of which will successfully log her into a secure system. a.

alexdok [17]

Answer:

The probability is $\frac{1}{n}$

Step-by-step explanation:

If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:

If k=1

$P = \frac{1}{n}$

Because, in her first try she has n possibles options and just one give her a successful login.

If k=2

$P=\frac{n-1}{n} *\frac{1}{n-1} =\frac{1}{n}$

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.

If k=3

$P=\frac{n-1}{n} *\frac{n-2}{n-1} *\frac{1}{n-2} = \frac{1}{n}$

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.

Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n

7 0

3 years ago

A random sample of pickles in a jar has the following weights, in grams: 68, 54, 59, 70, 69, 65, 73, 59, 74, and 54. What is the

aivan3 [116]

All the weight of the pickles or the mean is
58.5

6 0

4 years ago