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3 years ago

What is the solution to 3.2x = 6.4?

1 answer:

6 0

A. X = 2
what you do is divide each side by the coefficient of x (3.2) to get rid of it on the left, and simplify the right: 2.

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Meghan reduced the size of a rectangle to a height of 2 inches. What is the new width if it was originally 24 inches wide and 12

Zigmanuir [339]

Answer:

Step-by-step explanation:

2/12 = 1/6

24 * 1/6 = 4

12/24 = 2/x

12 x = 48

x = 4

or the original width was twice the length

twice 2 is 4

3 0

3 years ago

Classify the variable z in z square = 0.02 as rational or irrational

DochEvi [55]

Answer:

Irrational

Step-by-step explanation:

When we take the square root of both sides, we get z = 0.141421... and since there are no fractions and the decimals go endlessly on, it is irrational.

3 0

3 years ago

At a particular restaurant, each chicken wing has 60 calories and each slider has 225 calories. A combination meal with chicken

Elden [556K]

x = number of chicken wings

y = number of sliders

60x + 225y = 1380

2y + y = 1380

7 0

2 years ago

Suppose you pay $29.25 for a pair of shoes that has been discounted 35%. What is the original price of the shoes? Show how you i

Temka [501]

The answer is $30.

We know discounted price of the shoes - $24.
We need to find out the original price of the shoes - x.

The discounted price is 80% of the original price (it is said that shoes have been discounted 20%, so 100-20= 80%).

Let's set up a proportion. If $24 is 80%, how much is 100% (the original price):
$24 : 80% = x : 100 %

After crossing the products:
x = $24 * 100% / 80% = $30

Let's just check the result. After the discount of 20%, shoes will cost:
$30 - 20% = $30 - $30*(20/100) = $30 - $6 = $24.

The original price of the shoes is $30.

5 0

2 years ago

At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by –0.50t, in m/s^2 for t in seconds. By

anygoal [31]

The car's velocity at time $t$ is

$v(t)=16\dfrac{\rm m}{\rm s}+\displaystyle\int_0^t\left(\left(-0.50\frac{\rm m}{\mathrm s^2}\right)u\right)\,\mathrm du=16\dfrac{\rm m}{\rm s}+\left(-0.25\dfrac{\rm m}{\mathrm s^2}\right)t^2$

It comes to rest at

$v(t)=0\implies16\dfrac{\rm m}{\rm s}=\left(0.25\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=8.0\,\mathrm s$

Its velocity over this period is positive, so that the total distance the car travels is

$\displaystyle\int_0^{8.0}v(t)\,\mathrm dt=\left(16\dfrac{\rm m}{\rm s}\right)(8.0\,\mathrm s)+\frac13\left(-0.25\dfrac{\rm m}{\mathrm s^2}\right)(8.0\,\mathrm s)^3=\boxed{85\,\mathrm m}$

so the answer is D.

4 0

2 years ago