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ss7ja [257]
3 years ago
13

Describe how the graph of the parent function y= √x is transformed when graphing y= 3 √x-6. The graph is translated 6 units ____

?

Mathematics
2 answers:
Margarita [4]3 years ago
4 0

Answer:

Right . )

For the second answer is ( reflected over the x axis . )

The third one is stretch by a factor of 3 .

the fourth one is graph A

Step-by-step explanation:

irga5000 [103]3 years ago
3 0

The Answer: is ( Right . )

For the second answer is ( reflected over the x axis . )

The third one is stretch by a factor of 3 .

the fourth one is graph A

Step-by-step explanation:

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Answer:

B

Step-by-step explanation:

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3 years ago
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According to u.s. postal regulations, the girth plus the length of a parcel sent by mail may not exceed 108 inches, where by "gi
Pepsi [2]
Let x represent the side length of the square end, and let d represent the dimension that is the sum of length and girth. Then the volume V is given by
  V = x²(d -4x)
Volume will be maximized when the derivative of V is zero.
  dV/dx = 0 = -12x² +2dx
  0 = -2x(6x -d)
This has solutions
  x = 0, x = d/6

a) The largest possible volume is
  (d/6)²(d -4d/6) = 2(d/6)³
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b) The dimensions of the package with largest volume are
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8 0
3 years ago
The polygons are similar. Find the missing side length. NO LINKS!!!!​
timurjin [86]

Answer:

CD = 27

Step-by-step explanation:

Given the triangles are similar then the ratios of corresponding sided are equal, that is

\frac{CD}{KD} = \frac{CB}{KL} , substitute values

\frac{CD}{9} = \frac{30}{10} = 3 ( multiply both sides by 9 )

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7 0
3 years ago
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Rom4ik [11]

Answer:

49

Step-by-step explanation:

100- 51 = 49

7 0
4 years ago
Money Flow  The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the
77julia77 [94]

Answer:

Present value =  $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5%  compounded continuously

Now,

Accumulated Value of the money flow = 1000e^{0.05t}

The present value of the money flow = \int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt

= 1000\int\limits^4_0 {e^{0.015t}} \, dt

= 1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4

= 1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]

= 1000 × [70.7891 - 66.6667]

= $4,122.4

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8 0
3 years ago
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