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inna [77]
3 years ago
6

Make x the subject of the formula for Q20.

Mathematics
1 answer:
saul85 [17]3 years ago
7 0

Answer:

x = \sqrt{m(\frac{a}{b})^{2} +n  }

Step-by-step explanation:

a\sqrt{(\frac{x^{2} - n }{m}) } = \frac{a^{2} }{b}

\sqrt{\frac{x^{2} - n }{m} } = \frac{a}{b}   [Divide both sides by a]

\frac{x^{2} - n}{m} = (\frac{a}{b} )^{2}   [Square both sides]

x^{2} -n = m(\frac{a}{b} )^{2}   [Multiply both sides by m]

x^{2} =m(\frac{a}{b} )^{2}  + n   [Bring n to the right]

x = \sqrt{m(\frac{a}{b})^{2} +n  }   [Square root both sides]

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A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
mihalych1998 [28]

Answer:

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Step-by-step explanation:

1) Notation and definitions

X=1 number of citrus trees that are infected with the citrus red mite.

n=5 random sample taken

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p true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

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In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values would be given by:

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The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

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n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56  

And rounded up we have that n=6147

5 0
4 years ago
Mary's 3 hamsters each eat three-eighths of cup of grain a day, if she has 6 and 3/4 cups of grain, how many days will the grain
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I may be wrong let me know.
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