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sergeinik [125]
3 years ago
5

A farmer has 1235 trees to be planted on a rectangular parcel of land. if there are 24 trees planted in each row and each row mu

st be completed before it is planted, how many trees will be leftover planting?
a. 0
b. 11
c. 55
d. 21
Mathematics
1 answer:
kaheart [24]3 years ago
8 0

Answer:

c?

Step-by-step explanation:

It's the closest number to 51.

1245/24

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Find the inverse of g(x)=4/x+2
yulyashka [42]
I think it’s g^-1(x)= -2x+4

The “^” means exponent to -1 is the exponent of g

Hope I’m right !!
7 0
2 years ago
Use a known maclaurin series to obtain the maclaurin series for the given function. f(x = 8x2 tan?1(7x3
11Alexandr11 [23.1K]
Going out on a limb here and guessing that the function is

f(x)=8x^2\tan^{-1}(7x^3)

Please correct me if this isn't the case.

Recall that

\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^nx^{2n+1}}{2n+1}

which converges for |x|.

It follows that

8x^2\tan^{-1}(7x^3)=8x^2\displaystyle\sum_{n\ge0}\frac{(-1)^n(7x^3)^{2n+1}}{2n+1}
=\displaystyle\sum_{n\ge0}\frac{56(-49)^nx^{6n+3}}{2n+1}
6 0
4 years ago
Amy's grandmother gave her 3 identical chocolate chip cookies and 4 identical sugar cookies. In how many different orders can Am
Dmitrij [34]

Answer:

chocolate chip cookie first: 15 ways

chocolate chip cookie last: 15 ways

chocolate chip cookie first and last: 5 ways

Step-by-step explanation:

There is a total of 7 cookies.

Is she eats a chocolate cookie first, she will have 2 chocolate cookies and 4 sugar cookies (6 in total).

So, to find the number of different orders that Amy can eat the remaining cookies, we just need to calculate a combination of 6 choose 2 (that is, the number of ways we can put the 2 chocolate cookies among the 6 cookies) or a combination of 6 choose 4 (same thing, but for the sugar cookies):

C(6,2) = 6! / (2! * 4!) = 6 * 5 / 2 = 15 ways

Is she eats a chocolate cookie last, she will have 2 chocolate cookies and 4 sugar cookies (6 in total), so the problem is solved again with a combination of 6 choose 2:

C(6,2) = 15 ways

Is she eats a chocolate cookie first and last, she will have just 1 chocolate cookie left and 4 sugar cookies (5 in total), so the problem is solved with a combination of 5 choose 1 or a combination of 5 choose 4:

C(5,1) = 5! / (1! * 4!) = 5 ways

6 0
3 years ago
You have also set up a card game in which a player picks a card from a standard deck of 52 cards. The player wins if these two e
Alenkinab [10]

First, let's count:

there are 26 possible outcomes for E1 (black card)

there are 4x9 = 36 possible outcomes for E2, to pick a numbered card (any color)

there are 2x9 =18 possible outcomes for E1 (black) AND E2 (numbered, spade + clower)

the probability of E1 AND E2 is the ratio of the count of possible outcomes for E1 + E2 and the count of all possible outcomes (52 choices to pick a card from the deck):

P(E1 and E2) = 18/52 (34.6%)

And as asked:

P(E1) = 26/52 = 1/2 (50%)

P(E2) = 36/52 = 9/13 (69.2%)

5 0
3 years ago
If the side lengths of a cube are 14 feet, what is the correct way to write the expression to represent the volume of the cube i
Kryger [21]

Answer: Choice A) 14^3

This is the same as writing 14^3

===================================================

Explanation:

Since all the sides are 14 feet long, we can basically say length = width = height = 14.

Or put another way:

  • length = 14
  • width = 14
  • height = 14

The volume of the cube is length*width*height = 14*14*14 = 14^3 = 2744 cubic feet.

-----------

The term 14^3 has a base of 14 and exponent of 3.

The base is what we multiply out while the exponent tells us how many copies of the base to multiply. In this problem, we have 3 copies of 14 being multiplied. So that's why 14^3 = 14*14*14

If you were to say something like 3^14, then you would have 14 copies of 3 multiplied out, which is a much larger value. So we'll cross choice B off the list.

Choice C isn't correct either since again we're using exponents and not multiplication to tie together the 14 and 3.

Choice D would be correct if your teacher wanted it in expanded form, instead of exponent form.

6 0
3 years ago
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