Answer:
it already is in its simple form.
Converted to a decimal:
0.5 (rounded to 6 decimal places)
GCD:
1
Hopefully I helped answer your question.
Answer:
(25)^2*(9)^2*(4squreroot2)^2*(7squreroot2)^2
Step-by-step explanation:
5^4*3^3*2^5*343
=(25)^2*(9)^2*(4squreroot2)^2*(7squreroot2)^2
We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.
First of all, we will draw a triangle as shown in the attachment.
We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.
We know that sine relates opposite side of right triangle to hypotenuse.


Using inverse sine or arcsin, we will get:


Upon rounding to nearest degree, we will get:

Therefore, the measure of angle J is approximately 24 degrees.
-3 - 7 = -10
5 - -10= 15
m= -10/15 or -2/3
answer: y= -2/3x + 7