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dem82 [27]
3 years ago
11

What's 0.5 is 10 times as great as

Mathematics
1 answer:
Artemon [7]3 years ago
3 0
It is 0.05, all you have to to do is move the decimal to the left.
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Which numbers form a Pythagorean triple?
kipiarov [429]

Answer:

A. 9, 12, 15

Step-by-step explanation:

9, 12, 15 is a set of numbers that form pythagorean triple because it satisfies the equation, a² + b² = c².

Where, c is the longest side while a and c are the two other legs of the triangle.

Thus:

9² + 12² = 15²

225 = 225 (this is true).

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A wheel has a radius of 33 cm and completes 12 revolutions in 1 minute. a) determine the angular velocity of the wheel in radian
ZanzabumX [31]

Answer:

a) The angular velocity is 0.4π radians/second ⇒1.25664 radians/second

b) The wheel travels 124.4071 meters in 5 minutes ⇒ 39.6π meters

Step-by-step explanation:

The angular velocity ω = 2 π n ÷ t, where

  • n is the number of revolution
  • t is the time in second

The distance that moving by the angular velocity is d =  ω r t, where

  • r is the radius of the circle in meter

a)

∵ A wheel completes 12 revolutions in 1 minute

∴ n = 12

∴ t = 1 minute

→ Change the minute to seconds

∵ 1 minute = 60 seconds

∴ t = 60 seconds

→ Substitute n and t in the rule above

∵ ω = 2 (π) (12) ÷ 60

∴ ω = 24π ÷ 60

∴ ω = 0.4π radians/second

∴ The angular velocity is 0.4π radians/second ⇒1.25664 radians/second

b)

→ To find the distance in 5 minutes multiply ω by the radius by the time

∵ The wheel has a radius of 33 cm

∴ r = 33 cm

→ Change it to meter

∵ 1 m = 100 cm

∴ r = 33 ÷ 100 = 0.33 m

∵ t = 5 minutes

→ Change it to seconds

∴ t = 5 × 60 = 300 seconds

→ Substitute them in the rule of the distance above

∵ d = 0.4π (0.33) (300)

∴ d = 39.6π meters ⇒ 124.407 meters

∴ The wheel travels 124.4071 meters in 5 minutes ⇒ 39.6π meters

6 0
3 years ago
What is -10v – 3(8 + v)​
Alex73 [517]

-10v – 3(8 + v)​

mutiply the bracket by -3

(-3)(8)= -24

(-3)(v)= -3v

-10v-24-3v

-10v-3v-24 ( combine like terms)

answer:

-13v-24 or -24-13v

3 0
4 years ago
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