Answer:
B
Step-by-step explanation:
Also the answer must be under 9 so that rules out option D
Because We know CE = 2 and AD is visibly larger than CE, 6We can rule out option A
And that brings us down to B and C
CB is equal to 6, And I'm no genius, but I'm pretty sure AD is DEFINATLY not equal to 6.
so the answer is B
Answer:
p(4)=3
Step-by-step explanation:
p(4)=3(4)-9=12-9=3
A) > since it is 50c per weekday and 75c each weekend assuming it allows for the 2 days each saturday/sunday.
50c * 5 = $2.50 since there are 5 days in weekdays
75c * 2 = $1.50 since there are 2 days in the weekend
Add $2.50 and $1.50 to get $4.00
b) For 3 school days we know it is a weekday on the school week.
So perform 50c * 3 which gives us <span>$1.50
</span>c) 12 days off from school is 10 weekdays and 1 weekend or 2 days of 75c
So now just do 50c * 10 which is $5.00 and 75c * 2 which is $1.50
Add $5.00 and $1.50 and we get $6.50
d) 4 weeks = 20 weekdays since 5 *4 = 20 and 8 days in each weekend since 2 * 4 = 8
Now that we have the amount of weekdays and weekend days we can multiply.
50c * 20 = $10.00
75c * 4 = $3.00
Add $10.00 and $3.00 to get $13.00 for 4 weeks.
e) We have 1 day of the weekend and 2 weekdays here.
50c * 2 = $1.00
75c * 1 = 75c
<span>$1.00 + 75c = $1.75 in those 3 days listed.
</span>
Add all these together to get your total value.
$4.00 + $1.50 + $6.50 + $13.00 + $1.75 = $26.75
Answer:
20
Step-by-step explanation:
The midsegment of a trapezoid is calculated as
= 
= 
= 20
Answer:
Step-by-step explanation:
This is a d = rt problem; but since it is linear, then proportions will work too. Set up the proportion with miles on top and hours on the bottom:
Then put the numbers in where they go, keeping in mind that miles goes with miles and hours goes with hours in the ratios, and that our unknown is time (hours):
and cross multiply to solve:
638x = 4466 so
x = 7 hrs
