Question

What are the square roots of; (note: i think there are supposed to be 2 each) 36 12 1.96 0.64 400 25/36

Answer 1

Answer:

36 : 6 and -6

12 = $2\sqrt{3} , -2\sqrt{3}$

1.96 =1.4 and -1.4

0.64 : 0.8 and -0.8

400 : 20 and -20

25/36 = 5/6 and -5/6

Step-by-step explanation:

we know that

(-x)^2 = x^2

ALSO

(x)^2 = x^2

thus, square of both negative and positive number is same positive number.

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36 = 6*6

36 = -6*-6

hence

square roots of 36 is both -6 and 6

12 = 4*3 = $2^2*\sqrt{3} *\sqrt{3}$

$\sqrt{12} = 2\sqrt{3}$

also

12 = $-2\sqrt{3} *-2\sqrt{3}$

$\sqrt{12} = -2\sqrt{3}$

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1.96 = 196/100 = (14/10)^2

1.96 = 196/100 = (-14/10)^2

hence

$\sqrt{1.96} = 14/10 \ or -14/10$

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0.64 = 64/100 = (8/10)^2 = 0.8^2

0.64 = 64/100 = (-8/10)^2 = (-0.8)^2

Thus, square root of  0.64 = 0.8 and -0.8

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400 = 20^2

400 = (-20)^2

$\sqrt{400} = 20\\\sqrt{400} = -20$

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25/36 = (5/6)^2

25/36 = (-5/6)^2

$\sqrt{ 25/36} = 5/6 \\\sqrt{ 25/36} = (-5/6$