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Mashutka [201]
3 years ago
11

The volume of a cone is 62.8 cubic inches. The height of the cone is 15 inches. What is the radius of the cone, rounded to the n

earest inch? Use π = 3.14.
2 inches
4 inches
8 inches
9 inches
Mathematics
2 answers:
Leno4ka [110]3 years ago
6 0
I believe the answer is 2 inches
Salsk061 [2.6K]3 years ago
4 0

Answer:

R = sqrt 3 * (V /( pi * h))

V = 62.8

pi = 3.14

h = 15

now we sub

R = sqrt 3 * (62.8 / (3.14 * 15)

R = sqrt 3 * (62.6 / 47.1)

R = sqrt 3 * 1.33

R = sqrt 3.99

R = 1.9 rounds to 2 inches <===

Step-by-step explanation:

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Answer:

109n + 35

Step-by-step explanation:

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8 0
2 years ago
How do you solve 2 (5-6) &lt; 8f - 130
irga5000 [103]
2(5-6)<8f-130
(2x5)-(2x6)<8f-130
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-2+130<8f-130+130
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3 0
3 years ago
When 27 times x squared times z all over negative 3 times x squared times z to the fourth power is completely simplified, the ex
snow_lady [41]
Isolate z by itself:

\frac{z}{z^4}

To simplify variables with powers, subtract the smaller power from the bigger power:

4 - 1 = 3
\frac{z}{z^4} = \frac{1}{z^3} = z^{-3}

The exponent will be -3.
4 0
3 years ago
Read 2 more answers
in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)
Nimfa-mama [501]

Answer:

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

Step-by-step explanation:

Let \vec u and \vec a, from Linear Algebra we get that component of \vec u parallel to \vec a by using this formula:

\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a (Eq. 1)

Where \|\vec a\| is the norm of \vec a, which is equal to \|\vec a\| = \sqrt{\vec a\bullet \vec a}. (Eq. 2)

If we know that \vec u =(2,1,1,2) and \vec a=(4,-4,2,-2), then we get that vector component of \vec u parallel to \vec a is:

\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)

Lastly, we find the vector component of \vec u orthogonal to \vec a by applying this vector sum identity:

\vec  u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a} (Eq. 3)

If we get that \vec u =(2,1,1,2) and \vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right), the vector component of \vec u is:

\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10}    \right)

\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

4 0
3 years ago
Solve each of these equations. Explain or show your reasoning. 2(3x+2)=2x+28 5y+13=-43−3y 4(2a+2)=8(2−3a)
dalvyx [7]

Answer:

x = 6

y = 7

a = 1/4

Step-by-step explanation:

Equation 1:

2(3x+2) = 2x + 28

6x + 4 = 2x + 28

4x = 24

x = 6

Equation 2:

5y+13 = -43-3y

8y = -56

y = -7

Equation 3:

8a + 8 = 16 - 24a

32a = 8

a = 1/4

7 0
2 years ago
Read 2 more answers
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