Answer:
D
Step-by-step explanation:
i upload the image sorry i don't know how to explain i just search it
Answer:
A translation can map one angle unto another since dilations preserve angle measures of triangles
Step-by-step explanation:
The dilation of the figure by a scale factor of 4 gives an image that is 4 times the size of the original figure. However, the interior angles of the image and the original figure remain the same
A translation is a rigid transformation, such that the image and the preimage of a translation transformation have the same dimensions and angles
A translation of three consecutive non-linear points of the dilated image to the vertex and the two lines joining the corresponding point on the image, translates the angle at the given vertex
The above process can be repeated, to translate a second angle from the image to the preimage, from which it can be shown that the two figures are similar using Angle Angle, AA, similarity postulate
Answer:
hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to
Answer: v = 5v + 4u + 1.5sin(3t),
Step-by-step explanation:
u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1
v represents the "velocity function" i.e v = u'(t)
As v = u'(t)
<em>u' = v</em>
since <em>u' = v </em>
v' = u"
v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )
= 5v + 4u + 1.5sin(3t) ( noting that v = u' )
so v' = 5v + 4u + 1.5sin(3t)
d/dt ![\left[\begin{array}{ccc}u&\\v&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Du%26%5C%5Cv%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%26%5C%5C4%265%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26%5C%5C1.5sin%283t%29%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Given that u(1) = 1 and u'(1) = 2.5
since v = u'
v(1) = 2.5
note: the initial value for the vector valued function is given as
![\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Du%281%29%26%5C%5Cv%281%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}1\\2.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C2.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Answer:
Step-by-step explanation:
g(x)= -x-1 or g(x) = x+1
if g(x) = -x-1
-x-1=2x+4
-x=2x+5
-x/2=x+5
-x/2 -x=5
-x/2-2x/2=5
-x-2x=5
-3x=5
x=5/-3
if g(x) = x+1
x+1=2x+4
x=2x+3
x/2=x+3
x/2-x=3
x/2-2x/2=3
x-2x=3
-x=3
x=3
Hi there!
The answer is:
The range of a relation is the output (y) values of the relation. The range represents the set of the y-coordinates from the ordered pairs.
~ Hope this helps you!
