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2 years ago

If f(x) = 2x^3 - 3x + 1 find f(3)

1 answer:

7 0

Okay so what f(3) is saying is that x=3. You have to plug three in for x to make the new equation of 2(3)^3-3(3)+1 next you would do pemdas which is parethesis then exponets then multiplication/division then addition/subtraction to get 2*3=6 6^3 is 216 216-3*3 is 207 207+1 is 208 so the answer is f(3)=208

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Cooper is taking a multiple choice test with a total of 80 points available. Each question is worth exactly 4 points. What would

VLD [36.1K]

Answer:

80-4(2)=72; 80-4(x) if he got x wrong.

3 0

3 years ago

A company did a quality check on all the packs of trail mixes it manufactured. Each pack of trail mixes is targeted to weigh 9.2

saw5 [17]

If each pack of trail mixes is targeted to weigh 9.25 oz and must be within 0.23 oz of the target in order to be accepted, then rejected masses x, are those which weighs less than 9.02 oz or greater than 9.48 oz.

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2 years ago

Read 2 more answers

I need help fast please

Mademuasel [1]

306 cause 2448divided by 8

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2 years ago

Can somebody please help me i need this urgently.

sukhopar [10]

Answer:

multiple choice is worth 2

short response is worth 4

Step-by-step explanation:

23x + 10y = 86

28x + 5y = 76

solve by elimination

multiply the top by -1 and the bottom by 2

-23x + -10y = -86

56x + 10y = 152

add them

33x = 66

x = 2

with x = 2 plug x into one of the equations

23x + 10y = 86

23(2) + 10y = 86

46 + 10y = 86

10y = 40

y = 4

x = 2 and y = 4 so

multiple choice is worth 2

short response is worth 4

6 0

1 year ago

xand y are light house. y being 20km due east of x and from a ship due south of x the bearing of y was 055°. what is the distanc

leonid [27]

Answer:

I) |xz| ≈ 28.6 km

II) |yz| ≈ 34.8 km

Step-by-step explanation:

Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)

|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°

Using Trigonometric ratio - SOHCAHTOA

I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20

|xz| = 20 * Tan 55 = 20 * 1.428

|xz| = 28.56 km

|xz| ≈ 28.6 km

II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|

|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°

|yz| = 20 ÷ 0.574 = 34.84 km

|yz| ≈ 34.8 km

4 0

3 years ago