Answer:
The answer is below
Step-by-step explanation:
A triangle is a polygon with three sides and three angles. There are different types of triangles such as scalene triangle, equilateral triangle, isosceles triangle.
The area of a triangle is given as:
A = (1/2) * b * h
where b = base of triangle, h = height of triangle , A = area
Let BC = base = x, and AD = height = y, hence:
A = (1/2) * x * y = 0.5xy
If the lengths of AD and CB were both increased by 50%, hence:
new AD = y + 0.5y = 1.5y, new CB = x + 0.5x = 1.5x
The new area= (1/2) * 1.5y * 1.5x = 1.125xy
Increased area / area = 1.125xy / 0.5xy = 2.25
If the lengths are increased by 50%, the area would also increase and the new area would be 2.25 times
Answer:
Step-by-step explanation:
So we have the equation:
Add 2 to both sides. The left cancels:
Divide both sides by 6. The left cancels:
So, the value of x is -1.
And we're done!
So, to solve the questions on your paper, you need to first have all of the bottom numbers on the fractions similar numbers. So if you have the numbers 1/4 and 4/8, you need to get them to both be the same number. Therefore, 1/4 should become 2/8, because you doubled the bottom number (you also then need to do the same to the top number). You don't need to change 4/8, because it's bottom number is already 8. Then, you can take 4/8 and 1/8 and add them. To add them, you just add the top numbers. The top numbers make 5, so then you add the denominator, and make the number 5/8. Since you can't simplify 5/8, just keep it. But if it was 4/8, you could simplify it to 1/2. You can do all of this same to all of the numbers on your paper. :D If you are subtracting, subtract only the top numbers, but if you need to multiply or divide, multiply/divide both numerator AND denominator. :D I hope I helped! If I didn't, please tell me, or just delete my answer. :D
Answer:
Step-by-step explanation:
Let the cost of the item is C.
Case I :
first sale is applied
so, the price of item = one third = C - C/3 = 2C/3
Now coupon is applied
so, the price of item = 
= C/2
case II :
First coupon is applied
so, the price of item = C - C/4 = 3C/4
Now sale is applied
the price of item = 
= C/2
So, it does not matter that either coupon is applied first or the sale is applied first the final cost of the item remains same.
