Answer:
Event A = { Chevrolet , Buick }
Event B = { Ford , Lincoln }
Event C = { Toyota }
Step-by-step explanation:
- Mutually exclusive events are such that their probability of coming true simultaneously is zero. If we consider set notations we could say.
P (A & B) = P (B & C) = P (A & C) = 0
- In our case these events A,B, and C can be defined as:
Answer:
Event A = { Chevrolet , Buick }
Event B = { Ford , Lincoln }
Event C = { Toyota }
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer: You would need 5 men to paint a room in 3 hours
YWW :)
Answer:
4(R + 5 + R + 2) [Option B]
Step-by-step explanation:
<u>GIVEN :-</u>
- Length = R + 5
- Width = R + 2
<u>TO FIND :-</u>
- Perimeter of the rectangle
<u>FORMULAE TO BE USED :-</u>
For a rectangle with length 'l' and width 'w' , its perimeter = 4(l + w)
<u>SOLUTION :-</u>
Perimeter = 
= 
= 
