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UNO [17]
2 years ago
6

5

Mathematics
1 answer:
zepelin [54]2 years ago
6 0

The question is incomplete. Below you will find the missing figure.

Two friends, Andrew and Liz, are playing a game using this spinner. If the

spinner lands on region 2 or 3, Andrew wins. If it lands on region 4, Liz wins. If it lands on any other region, neither wins. Is this a fair game?

A. Yes. Each friend has a 1/4 probability of winning.

B. Yes. Each friend has a 1/6 probability of winning.

C. No. Andrew has a probability of 1/4 winning and Liz has a probability of 1/6 winning.

D. No. Andrew has a probability of 1/3 winning and Liz has a probability of 1/4 winning.

The correct option is Option A: Yes. Each friend has 1/4 probability of winning.

Probability is the possibility of an event to happen which is the ratio of no. favorable outcomes and no. of total outcomes.

P = no. of favorable outcome/ total no. of outcome

Here given in the question,

If the spinner touches region 2 or 3, Andrew wins

If the spinner touches region 4, Liz wins.

This is fair play because both have the same size of region for winning.

If we cut the circle into 8 pieces,

as region 1 is the sum of 2 sub-parts of the circle,

possibility of spinner touching region 1= 2/8= 1/4

possibility of spinner touching the small region = 1/8

So the possibility of the spinner touching the region 2or 3= 1/8+1/8= 2/8= 1/4

Hence the possibility of Andrew wins= possibility of the spinner touching region 1= 1/4

possibility of Liz wins= possibility of the spinner touching the region 2 or 3= 1/4

Therefore the correct option is Option A: Yes. Each friend has 1/4 probability of winning.

Learn more about the probability

here: brainly.com/question/24756209

#SPJ10

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Answer:

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