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3 years ago

Solve x^2+8x+10=3 by completing the square

Mathematics

2 answers:

Nikolay [14]3 years ago

7 0

Answer:

Use the formula

(b/2)^2

in order to create a new term. Solve for x

by using this term to complete the square.

x=−1,−7

tatiyna3 years ago

6 0

Answer:

x = -1 and x = -7

Step-by-step explanation:

Rewrite x^2+8x+10=3 as x^2 + 8x + 10=3

Now identify the coefficient of the x term.

It is 8. Halve that, getting 4, and then square

this result, getting 16.

Now add 16 and then subtract 16 in x^2 + 8x + + 10=3, as

follows: x^2 + 8x + 16 - 16 + 10=3

Simplify this in two ways: First, rewrite x^2 + 8x + 16 as (x + 4)^2, and

Combine -16 and 10: -6

and rewrite the equation as (x + 4)^2 - 6 = 3

Now add 6 to both sides: (x + 4)^2 = 9

Take the square root of both sides:

x + 4 = ±3

Then x = -4 + 3 and x = -4 -3, or x = -1 and x = -7

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3 years ago

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adoni [48]

Step-by-step explanation:

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3 years ago

Find the volume and area for the objects shown and answer Question

klio [65]

Step-by-step explanation:

You must write formulas regarding the volume and surface area of the given solids.

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$\\\text{we need to calculate the height of two different side walls}\ h_1\ \text{and}\ h_2\\\text{use the Pythagorean theorem:}\\\\h_1^2=\left(\dfrac{l}{2}\right)^2+h^2\to h_1=\sqrt{\left(\dfrac{l}{2}\right)^2+h^2}=\sqrt{\dfrac{l^2}{4}+h^2}=\sqrt{\dfrac{l^2}{4}+\dfrac{4h^2}{4}}\\\\h_1=\sqrt{\dfrac{l^2+4h^2}{4}}=\dfrac{\sqrt{l^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{l^2+4h^2}}{2}$

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$SA=lw+2\cdot\dfrac{lh_1}{2}+2\cdot\dfrac{wh_2}{2}\\\\SA=lw+2\!\!\!\!\diagup\cdot\dfrac{l\cdot\frac{\sqrt{l^2+4h^2}}{2}}{2\!\!\!\!\diagup}+2\!\!\!\!\diagup\cdot\dfrac{w\cdot\frac{\sqrt{w^2+4h^2}}{2}}{2\!\!\!\!\diagup}\\\\SA=lw+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw}{2}+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw+l\sqrt{l^2+4h^2}+w\sqrt{w^2+4h^2}}{2}$

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3 years ago