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Nadya [2.5K]
3 years ago
15

Three times theWhich equation represents, "three times the difference of a number and four is equal to 5"?

Mathematics
1 answer:
mezya [45]3 years ago
6 0
3(x-4)=5


Take it in the order than it is transmitted 4 times the difference of a number which means to switch the order


Mark brainliest please
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I believe the answer is:

1+3.000000000i

I am making an educated guess, so sorry if I am wrong.

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Question : 4(3x + 2) -6 x 6
Varvara68 [4.7K]

Answer:

x= 24

Step-by-step explanation:

open the bracket

4×3x =12x + 4 × 2 =8

12×+ 8-6×6

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For every 4 miles vanessa jogged cody jogged 3 miles if vanessa jogged 1 miles how far did cody have jogged
Sergio [31]

divide 3 by 4 = 3/4 = 0.75

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3 years ago
5. Find the discriminant of 15x2 = 4x – 1 and describe
diamong [38]

Answer:

a) The discriminant of the equation =  - 44

b)The nature of the roots will be imaginary.

c) x = \frac{2 +\sqrt{11} i}{15}  or, x = \frac{2 - \sqrt{11} i}{15}

Step-by-step explanation:

Here, the given expression is 15x^{2}  = 4x -1

or, 15x^{2}  -  4x + 1   = 0

Now the discriminant (D) of a quadratic equation ax^{2}  +b x + c   = 0

D = b^{2}   -  4ac  = (-4)^{2}  -  4(15) (1)  = 16 - (60) = -44

Hence, the discriminant of the equation =  - 44

As D< 0, so the roots will be imaginary.

Now,by quadratic formula : x = \frac{-b \pm \sqrt{b^{2}  - 4ac} }{2a}

So, here x = \frac{-(-4) \pm \sqrt{D} }{2a}  = \frac{4 \pm \sqrt{(-44 )} }{30}

So, either x = \frac{4 + \sqrt{(-44 )} }{30} or, x =  \frac{4 - \sqrt{(-44 )} }{30}

or, x = \frac{2 +\sqrt{11} i}{15}  or, x = \frac{2 - \sqrt{11} i}{15}

8 0
3 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
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