For the answer to the question above, <span>Well, first let us put up a functional equation. </span>
<span>Since this is an exponential function, it'll be: f(t)=54,000*1.03^t </span>
<span>But we want to know how many wolves there were 10 years ago. </span>
<span>For that, we simply "turn time around", as in: f(t)=54,00*1.03^-t </span>
<span>This displays a decreasing number of wolves, as you turn back time. </span>
<span>Now we simply calculate 54,000*1.03^-10 </span>
<span>which is approximately 40,200?</span>
The first thing you want to do is plug in x and y into both equations:
a(3) + b(4) = 4
b(3) + a(4) = 8
rearrange to line up a’s and b’s
3a + 4b = 4
4a + 3b = 8
now you want to choose a or b and multiply each equation by a number to make them have the same amount of a’s or b’s.
4(3a + 4b = 4) = 12a + 16b = 16
3(4a + 3b = 8) = 12a + 9b = 24
Now we subtract the bottom equation from the top and solve for b:
12a + 16b - (12a + 9b) = 16 - 24
7b = -8
b = -8/7
Now we plug back in for b to one of the original equations:
3a + 4(-8/7) = 4
3a + (-32/7) = 4
3a - (32/7) = 4
3a = 4 + (32/7)
3a = (28/7) + (32/7)
3a = 60/7
a = (60/7)/3 = 20/7.
Finally, plug a and b in together to double check using the second equation.
4a + 3b = 8
4(20/7) + 3(-8/7) = ?
(80/7) - (24/7) = ?
56/7 = 8.
The answer to this one is<em> xy + 4</em>
The range would be most affected due to without it, the range would be a lot less. Median is also affected, but not as greatly.
Answer:
The required probability is 0.1667
Step-by-step explanation:
Consider the provided information.
According to Probability Density Function: 
Therefore,
The probability that such errors will be between –0.002 and 0.003 is:
![P(-0.002\leq x\leq 0.003)=\frac{1}{0.030}[x]^{0.003}_{-0.002}](https://tex.z-dn.net/?f=P%28-0.002%5Cleq%20x%5Cleq%200.003%29%3D%5Cfrac%7B1%7D%7B0.030%7D%5Bx%5D%5E%7B0.003%7D_%7B-0.002%7D)
Hence, the required probability is 0.1667
