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Ivenika [448]
3 years ago
12

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the given sample data. An experiment was conducted to determin

e whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Listed below are the phenotype codes where 1 equals smooth dash yellow​, 2 equals smooth dash green​, 3 equals wrinkled dash yellow​, and 4 equals wrinkled dash green. Do the results make​ sense? 1 3 4 1 3 2 3 4 3 4 1 4 3 3
Mathematics
1 answer:
egoroff_w [7]3 years ago
5 0

Answer:

The mean phenotype code is 2.72

The median phenotype code is 2.52

The mode phenotype code is 2.

The midrange of the phenotype codes is 2.52

B Only the mode makes sense since the data is nominal.

Step-by-step explanation:

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Evacuate the following using suitable identities (102)^3
snow_lady [41]

The value of (102)^3 exists 1061208.

<h3>How to estimate the value of (102)^3?</h3>

Let us rewrite (102)^3 as (100+2)^3

Now utilizing the identity (a+b)^3=a^3+b^3+3ab(a+b), we get

a = 100 and b = 2 then substitute the values of a and b then

(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]

= 1000000 + 8 + (600 × 102)

= 1000000 + 8 + 61200

= 1061208

Hence, (102)^3=1061208

Therefore, the value of (102)^3 exists 1061208.

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Step-by-step explanation:

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Let's take a look at each end.

As x approaches negative infinity:

As x approaches the left towards negative infinity, we can see that the graph is shooting straight upwards.

Therefore, as x\rightarrow-\infty, our function f(x) is increasing and increasing up towards positive infinity.

Therefore, the end behavior at the left will be:

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As x approaches the right towards positive infinity, we can see the that graph is also shooting straight upwards.

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