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3 years ago

What is the slope of the line represented by the equation

Mathematics

1 answer:

Pie3 years ago

7 0

Answer:

The slope is -3/4

Step-by-step explanation:

3x+4y = 8

We want to get the equation in slope intercept form

y = mx+b where m is the slope

Subtract 3x from each side

3x+4y-3x= -3x+8

4y = -3x+8

Divide by 4

4y/4 = -3x/4 +8/4

y = -3/4x +2

The slope is -3/4 and the y intercept is 2

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Sally is planning a trip for 225 students

Gala2k [10]

Answer: 75 students.

Step-by-step explanation:

In the data set we have a total of 10 + 8 + 7 + 5 = 30 students.

of those, 10 want to go to the park, the percentage is:

(10/30)*100% = 33.3%

Then, out of the 225, we can expect that a 33.3% (or 0.333 in decimal form) want to go to the park, this is:

N = 225*0.333% = 74.925

We can roud it up, and get N = 75

So Sally can expect that 75 students want to go to the park

4 0

2 years ago

Factorise 24p2 + pq - 23q²

Novosadov [1.4K]

24p² + pq - 23q² =

= 24p² + 24pq - 23pq - 23q²

= 24p(p + q) - 23q(p + q)

= (p + q)(24p - 23q)

3 0

3 years ago

Someone help me please, 25 points

ycow [4]

A. (x+8)^ 2 + 1
B. (x-3)^ 2 - 8
C. ( x - 3/2) ^ 2 - 1/4

4 0

1 year ago

Buck lodge israising money for hoops for heart in the spring. They raise $1000 in the fall and are asking the students to bring

Wewaii [24]

Answer: a) The function :

f(x) = 5x + 1000

b) f(x) = 2250 dollars

Step-by-step explanation: Please find the attached file for the solution

4 0

2 years ago

5. A ball is thrown straight up leaving the player's hands at at 7.5 m/s. If air resistance is ignored, how high can the ball tr

aleksley [76]

The maximum height reached is 2.87 meters

<h3>What is maximum height?</h3>

The maximum height of an object is the highest vertical position along the trajectory of the object.

The given parameters are:

$u = 7.5ms^{-1}$ --- the initial velocity
$v = 0ms^{-1}$ --- the final velocity
$a =-g$ --- the acceleration

To calculate the height (s) of the ball, we make use of the following equation of motion:

$v^2 = u^2 + 2as$

Substitute known values

$0^2 = 7.5^2 - 2gs$

$0 = 56.25 - 2gs$

Collect like terms

$2gs = 56.25$

Substitute 9.8 for g

$2 \times 9.8 s = 56.25$

$19.6 s = 56.25$

Divide both sides by 19.6

$s = 2.87$

Hence, the maximum height reached is 2.87 meters

Read more about acceleration and maximum height at:

brainly.com/question/14638187

3 0

2 years ago