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4 years ago

Can you please answer my question? WILL MARK BRAINIEST!

Mathematics

2 answers:

solniwko [45]4 years ago

8 0

What is your question.

avanturin [10]4 years ago

5 0

What is your question

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Hii. can you answer pt b? thxx

kiruha [24]

There would be little to no change, due to the fact of there being little change anyway looking at the current plots, and table.

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4 years ago

Read 2 more answers

A company has manufactured certain objects and has printed a serial number on each manufactured object. The serial numbers start

elixir [45]

Answer:

Attached is the full explanation:

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3 years ago

In the figure above, PQRS is a circle. If PQT and SRT<br>are straight lines, find the value of x.

Elena L [17]

Given:

PQRS is a circle, PQT and SRT are straight lines.

To find:

The value of x.

Solution:

Since PQRS is a circle, PQT and SRT are straight lines, therefore, PQRS isa cyclic quadrilateral.

We know that, sum of opposite angles of a cyclic quadrilateral is 180 degrees.

$m\angle SPQ+m\angle QRS=180^\circ$

$81^\circ+m\angle QRS=180^\circ$

$m\angle QRS=180^\circ-81^\circ$

$m\angle QRS=99^\circ$

Now, SRT is a straight line.

$m\angle QRT+m\angle QRS=180^\circ$ (Linear pair)

$m\angle QRT+99^\circ=180^\circ$

$m\angle QRT=180^\circ-99^\circ$

$m\angle QRT=81^\circ$ ...(i)

According to the Exterior angle theorem, in a triangle the measure of an exterior angle is equal the sum of the opposite interior angles.

Using exterior angle theorem in triangle QRT, we get

$m\angle PQR=m\angle QRT+m\angle QTR$

$x=81^\circ+22^\circ$

$x=103^\circ$

Therefore, the value of x is 103 degrees.

4 0

3 years ago

PLEASE HELP I WILL GIVE BRAINLIEST!!!!! I already solved for x please solve for y and z! Trolls are getting reported and banned

hoa [83]

Not sure if your the same person but I had already done the work for this problem....

4 0

3 years ago

6(m-1) = 3(3m + 2) Show all work

nordsb [41]

Answer:

$\boxed{\sf m = -4}$

Step-by-step explanation:

$\sf Solve \: for \: m: \\ \sf \implies 6 (m - 1) = 3 (3 m + 2) \\ \\ \sf Expand \: out \: terms \: of \: the \: left \: hand \: side: \\ \sf \implies 6 m - 6 = 3 (3 m + 2) \\ \\ \sf Expand \: out \: terms \: of \: the \: right \: hand \: side: \\ \sf \implies 6 m - 6 = 9 m + 6 \\ \\ \sf Subtract \: 9 m \: from \: both \: sides: \\ \sf \implies (6 m - 9 m) - 6 = (9 m - 9 m) + 6 \\ \\ \sf 6 m - 9 m = -3 m: \\ \sf \implies -3 m - 6 = (9 m - 9 m) + 6 \\ \\ \sf 9 m - 9 m = 0: \\ \sf \implies -3 m - 6 = 6 \\ \\ \sf Add \: 6 \: to \: both \: sides: \\ \sf \implies (6 - 6) - 3 m = 6 + 6 \\ \\ \sf 6 - 6 = 0: \\ \sf \implies -3 m = 6 + 6 \\ \\ \sf 6 + 6 = 12: \\ \sf \implies -3 m = 12 \\ \\ \sf Divide \: both \: sides \: of \: -3 m = 12 \: by \: -3: \\ \sf \implies \frac{ - 3m}{ - 3} = \frac{12}{ - 3} \\ \\ \sf \frac{ - 3}{ - 3} = 1: \\ \sf \implies m = \frac{12}{ - 3} \\ \\ \sf - \frac{12}{3} = - 4 : \\ \sf \implies m = - 4$

7 0

3 years ago