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<h3>Final value : x² -9x - 11</h3>
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<h3>Step by step </h3>




2x + 1 = ⅕ × (x² + x - 6)
2x + 1 = ⅕x² + ⅕x - 6/5
1/5x² +1/5x - 2x - 6/5 - 1 = 0
1/5x² -9/5x - 11/5 = 0
x² - 9x - 11 = 0. #times by 5
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#Give me brainliest pls im tired typing all of this
Answer:
H and J
Step-by-step explanation:
Let
. The gradient of
at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.
So the tangent plane has equation

Compute the gradient:

Evaluate the gradient at the given point:

Then the equation of the tangent plane is

Answer:
I will try:
Step-by-step explanation:
Note: ∈ means 'belongs to the set of' and <em>R</em> is 'the set of all real numbers'
Inequality:
- Domain is: x ∈ <em>R</em>
- Range is: x ≥ -2
Set:
-Domain is: {x| x ∈ <em>R</em>}
- Range is: {y| y ≥ -2}
Interval:
- Domain is: (-∞,∞)
- Range is: [-2, ∞)
g(x) is stretched by a factor of 4 and translated 2 units down.