Solve using square roots 3x^2+25=73

1 answer:

4 0

Heya !

Given expression -

$3 {x}^{2} + 25 = 73$

Subtracting 25 both sides ,

$3 {x}^{2} + 25 - 25 = 73 - 25 \\ \\ 3 {x}^{2} = 48$

Dividing by 3 on both sides ,

$\frac{3 {x}^{2} }{3} = \frac{48}{3} \\ \\ {x}^{2} = 16$

Therefore ,
$x = + \: 4 \: \: \: \: or \: \: - 4 \: \: \: \: \: \: \: Ans.$

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Geometry question. please help

Vinvika [58]

Answer:

The length of PQ is 18 feet.

The length of PR is 18 feet.

The length of QR is 24 feet.

Step-by-step explanation:

A way to set an equation up for this problem is:

$\frac{4}{3}x+x+x=60$

where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.

Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:

$\frac{4}{3}(18)+18+18=60$

Don’t solve the whole equation, just solve the $\frac{4}{3}(18)$ part of the equation, which is equal to 24. So the final equation is this:

$24+18+18=60$

Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).

Sorry for the long explanation.

But hope this helps and answers your question :)

8 0

2 years ago

Suppose that demand in period 1 was 7 units and the demand in period 2 was 9 units. Assume that the forecast for period 1 was fo

Zepler [3.9K]

Answer:

Step-by-step explanation:

Forecast for period 1 is 5

Demand For Period 1 is 7

Demand for Period 2 is 9

Forecast can be given by