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mote1985 [20]
3 years ago
5

Stuck on this.. anyone down to help?

Mathematics
2 answers:
MArishka [77]3 years ago
6 0

this one you can solve easily.

take each equation and put number of miles in that , calculate cost and compare the table.

for example

taking first equation

c = 0.15m + 5.75

noe.from table take m = 10, after putting this we should get cost equal to 5.75 as mentioned in table.

c = 0.15×10 + 5.75 = 7.25 ≠ 5.75

so ignore this and take next equation

c = 0.15m + 4.25

m =10

c = 0.15×10 + 4.25 = 5.75

which matches with our table. putting other values of m from table gives us the right cost mentioned in table . so answer is option B

you can verify that no other equation satisfies the table data.

emmasim [6.3K]3 years ago
3 0

Answer:

B

Step-by-step explanation:

C and D dont make since to the problem

so i was left was A and B and i can't realy how i got my answer but i came down B

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For her college fund jenny's parents invested $5000 four years ago. the account has now reached $6312. what is the approximate a
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Answer:

Rate = 6.56%

Step-by-step explanation:

Principal (P) = $5000

Interest (I) = $6312

Time (T) = 4 years

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S.I = P(1 + rt)

S.I = simple interest

P = principal

R = Rate

T = Time

6312 = 5000(1 + r*4)

6312 = 5000 + 5000*4r

6312 - 5000 = 20000r

1312 = 20000r

r = 1312 / 20000

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4 0
3 years ago
What is four hundred fifty two divided by four?
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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
16. Let W be the set of all vectors in R3 of the form a+2b b -3a Find a basis for Wand state the dimension of W.
Yuki888 [10]

Answer:

W=\{\left[\begin{array}{ccc}a+2b\\b\\-3a\end{array}\right]: a,b\in\mathbb{R} \}

Observe that if the vector x=\left[\begin{array}{ccc}x\\y\\z\end{array}\right] is in W then it satisfies:

\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]

This means that each vector in W can be expressed as a linear combination of the vectors \left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]

Also we can see that those vectors are linear independent. Then the set

\{\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]\} is a basis for W and the dimension of W is 2.

7 0
3 years ago
What is 15-5(4x-7)=50
katovenus [111]

Simplifying

15 + -5(4x + -7) = 50


Reorder the terms:

15 + -5(-7 + 4x) = 50

15 + (-7 * -5 + 4x * -5) = 50

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Combine like terms: 15 + 35 = 50

50 + -20x = 50


Add '-50' to each side of the equation.

50 + -50 + -20x = 50 + -50


Combine like terms: 50 + -50 = 0

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Combine like terms: 50 + -50 = 0

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Solving

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Solving for variable 'x'.


Move all terms containing x to the left, all other terms to the right.


Divide each side by '-20'.

x = 0.0


Simplifying

x = 0.0

5 0
3 years ago
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