Question

What is the value of this expression when m=3 and n=-5 (6m^-1n^0)^-3

Answer 1

This is

(6(3)^-1 (-5)^0)^-3

=  (6/3 * 1)^-3

= (2)^-3

= 1/8  Answer

Answer 2

Answer:

$\frac{1}{8}$

Step-by-step explanation:

Given expression is,

$(6m^{-1}n^0)^{-3}$

$=(6m^{-1})^{-3}$   ( $a^0 =1$ )

$=6^{-3} (m^{-1})^{-3}$   ( $(ab)^m=a^mb^m$ )

$=6^{-3} m^{-1\times -3}$    ( $(a^m)^n=a^{mn}$ )

$=6^{-3} m^3$

$=\frac{m^3}{6^3}$             ( $a^m=\frac{1}{a^{-m}}$ )

$=\frac{m^3}{216}$

We have, m = 3

$=\frac{3^3}{216}$

$=\frac{27}{216}$

$=\frac{1}{8}$