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4vir4ik [10]
2 years ago
6

SOMEONE PLEASE PLEASE HELP ME ON THIS!!

Mathematics
2 answers:
erik [133]2 years ago
5 0

\frac{x}{20} =\frac{14}{8} \\x=\frac{14}{8}  \times 20=35Answer:

35

Step-by-step explanation:

MArishka [77]2 years ago
4 0

X=22

14 plus 8 gives you x

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Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).
Vanyuwa [196]
L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\\\\(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\\\\(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\\\\(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\\\dots-3c^4a^2+3c^2a^4-a^6\\\\=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)

R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R
5 0
3 years ago
Read 2 more answers
What is the value of expression below 56 ÷ 1/17
Mariulka [41]

56 \div  \frac{1}{17}  \\  = 56 \times  \frac{17}{1}  \\  = 56 \times 17 \\  = 952

Hope this helps.
4 0
3 years ago
Pls help me I have 5 min to do this!!!! PLS PLS PLS PLS PLS NO LINKS!!!! I can’t open them just pls give me the answer idc how y
nadezda [96]

Answer:

P(-8,6), Q(-5,2), R(2,1)

8 0
3 years ago
Please Help I will do Brainliest for first and correct answer
Soloha48 [4]

Answer:

5

Step-by-step explanation:

41 - 32 = 9

5/9 x 9 = 5

8 0
3 years ago
I need help with geometry plz
Softa [21]

Answer:

Point A is -2, 1

Point B is -4, -2

Point C is -4, -6

and D is -1, 3.

Step-by-step explanation:

Irdk if this is all right bcz its kinda hard to see the exact points. Hope it is tho, and hope it helps you out! Good luck :P

4 0
3 years ago
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