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katen-ka-za [31]
3 years ago
7

For what values of t on the interval [0, 21 ]is the instantaneous velocity positive​ (the projectile moves​ upward)?

Mathematics
1 answer:
OLEGan [10]3 years ago
8 0

Answer:

0 <=t<=21

Step-by-step explanation:

Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below  0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).

hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).

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124 ounces decreased by 67%
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8 0
3 years ago
Can pls someone help me with my homework
Wewaii [24]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Let t be time in seconds and let r(t) be the rate, in gallons per second, that water enters a reservoir: r(t)=700−40t. a) For 0≤
Flura [38]
What you don't want is the value of r(t) becoming negative. Surely that would represent water escaping the reservoir.

How big can (t) get before water actually starts escaping the reservoir?

Essentially, to figure this out r(t) would have to be equal to 0. 

700 - 40t = 0

40t=700

t=700/40=17.5

So the first answer is 17.5 seconds. After this amount of time has elapsed the reservoir will start to lose water as r(t) would become negative.

---------------

The reservoir had the least amount of water in it before it was being filled. That was when t=0. The volume of water in the reservoir wasn't negatively impacted as not enough water had escaped it during the 17.5 to 30 second period.
7 0
3 years ago
Quadratic function that opens downward with vertex, not in origin
Vinvika [58]

Answer: The graph of a quadratic function is called a parabola. ... There is an easy way to tell whether the graph of a quadratic function opens upward or downward: if the leading coefficient is greater than zero, the parabola opens upward, and if the leading coefficient is less than zero, the parabola opens downward.

Step-by-step explanation:

5 0
3 years ago
6 2/9 ÷ (-2 2/3)<br>please help​
zubka84 [21]
  • <em>Answer:</em>

<em> - 2 1/3</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>6  2/9 : ( - 2 2/3) =</em>

<em>= (6*9+2)/9 : -(2*3+2)/3</em>

<em>= 56/9 : - 8/3</em>

<em>= 56/9 × - 3/8</em>

<em>simplify 56 - 8 ; 9 - 3</em>

<em>= 7/3 × - 1/1</em>

<em>= - 7/3</em>

<em>= - 2 1/3</em>

<em>Good luck !</em>

<em />

6 0
3 years ago
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