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3 years ago

For what values of t on the interval [0, 21 ]is the instantaneous velocity positive (the projectile moves upward)?

Mathematics

1 answer:

OLEGan [10]3 years ago

8 0

Answer:

0 <=t<=21

Step-by-step explanation:

Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below 0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).

hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).

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The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in <em>fourth</em> quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in <em>4th quadrant </em>so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

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3 years ago

Jose has $20 and is saving $6 per week. Ana has $150 and is spending $4 per

Softa [21]

No they wont have the same amount of money ana has more than jose and he’s spending more and wont have enough for the whole week, while ana will have enough and she’s only wasting 4$....

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3 years ago

The 100th term of 70, 100, 130

fgiga [73]

Answer:

3040

Step-by-step explanation:

given arithmetic progression is

70,100,130,...

here

first term (a)=70

common difference (d)=100-70=30

number of term n=100

using the formula of arithmetic progression

an=a+(n-1)d

a100=70+(100-1)30

a100=70+99×30

a100=70+2970

a100=3040

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2 years ago

A train traveled 217 miles at an average speed of 62mph. for how many hours did the train travel

Natasha2012 [34]

Well, 217 miles ÷ 62 MPH is 3.5.
so it took the train 3.5 hours.

check it: 62 MPH x 3.5 hours, it went 217 miles

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3 years ago

Which of the following is not equal to 6.7

kondor19780726 [428]

Answer: i think your missing the other part of the question

Step-by-step explanation:

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3 years ago

For what values of t on the interval [0, 21 ]is the instantaneous velocity positive​ (the projectile moves​ upward)?

For what values of t on the interval [0, 21 ]is the instantaneous velocity positive (the projectile moves upward)?