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3 years ago

Help cant seem to figure out.

Mathematics

2 answers:

Dafna1 [17]3 years ago

5 0

Answer:

For a cylinder there is 2 kinds of formulas the lateral and the total. the lateral surface area is just the sides the formula for that is 2(pi)radius(height). the formula for the total surface area is 2(pi)radius(height) + 2(pi)radius squared.

Vadim26 [7]3 years ago

5 0

The equation for the surface are of a cylinder is 2 pi r h +2 pi r ^2
That’s means the equation is 2 pi 30 + 2 pi 9 which equals 245cm

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What is 2/3 + __=1 4/9

g100num [7]

You turn 2/3 into 6/9
Then turn 1 4/9 into an improper fraction 13/9
Then subtract and you get 7/9

The answer is 7/9

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If F(x) =3x-2/6 which of the following is the inverse of f(x)

marissa [1.9K]

Answer:

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Step-by-step explanation:

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if $f(x)=(3x-2)/6$

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3 years ago

Read 2 more answers

Evaluate the infinite sum:

satela [25.4K]

Consider the k-th partial sum,

$S_k = 1 + \dfrac2\pi + \dfrac3{\pi^2} + \cdots + \dfrac k{\pi^{k-1}}$

More compactly,

$\displaystyle S_k = \sum_{i=1}^k \frac i{\pi^{i-1}} = \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}}$

(this is just another case of a similar sum you asked about a while ago [24494877])

The infinite sum is the limit of the partial sum as k goes to infinity. We have

$\displaystyle \lim_{k\to\infty} \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}} = \frac\pi{(1-\pi)^2} \lim_{k\to\infty} \left(\frac{(1-\pi)k}{\pi^k} + \pi - \frac1{\pi^{k-1}} \right) = \boxed{\frac{\pi^2}{(1-\pi)^2}}$

since the non-constant terms in the limit converge to 0.

Alternatively, recall that for |x| < 1, we have

$\dfrac1{1-x} = \displaystyle \sum_{n=0}^\infty x^n$

Differentiating both sides gives

$\dfrac1{(1-x)^2} = \displaystyle \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1}$

also valid for |x| < 1. Take x = 1/π and you get the sum you want to compute.

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2 years ago