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pashok25 [27]
3 years ago
15

Help me for 4??????????

Mathematics
2 answers:
sp2606 [1]3 years ago
6 0
35% put into a decimal is .35, and if you convert .35 to a fraction you get 7/20 which cannot be simplified, therefore 7/20 is 35% of the shoes in simplest fraction form.
Oksanka [162]3 years ago
3 0
The fraction would be 7 over 20, or 7/20
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Attached please find my maths problem to be solved and graphed
ki77a [65]

Answer:

Attached is the sketch

X-axis intersections:

(-3,0)

(0,0)

(1,0)

Points of inflection:

(-1,319,-2.881) Concave upward

(0.569,1.041) Concave downward

Step-by-step explanation:

Desmos (I'm not allowed to post the link, pls search it up) is a great help for these type of problems!

8 0
3 years ago
Hey square piano has an area of 200 ft.² how long is each side of the piano to the nearest 0.05
sergey [27]
Since all sides of the square are equal, therefore area of square can be calculated using the following rule:
area of square = side^2
200 = (side length)^2
therefore,
the length of each side is sqrt(200) = 14.14 ft
4 0
3 years ago
Phil is riding his bike. He rides 54 miles in 4 hours, 67.5 miles in 5 hours, and 81 miles in 6 hours. Find the constant of prop
AleksandrR [38]

Answer:

K=13,5

y=13,5x, x=numbers of hours

Step-by-step explanation:

To find the  proporcionality constant, divide the number of milles traveled in given time.

K=54/4=67,5/5=81/6=13.5 and the equation that describes the relationship is y=13,5x

3 0
3 years ago
Read 2 more answers
Who wants to help i really dont wanna do this question
SOVA2 [1]

Answer:

71

Step-by-step explanation:

(2x² = 2 × 5² = 2 × 25) + ([4x = 4 × 5 = 20] + 1)

(50) + (21) = 71

5 0
2 years ago
The nth term of a sequence is 3n^2- 1
Thepotemich [5.8K]

Answer: The number that belongs to both sequences is 26.

Step-by-step explanation:

We have two sequences, let's call one as A and the other as B.

The n-th term of sequence A is written as:

aₙ = 3*n^2 - 1

the nth term of sequence B is written as:

bₙ = 30 - n^2

We want to find a term that belongs to both sequences, (it can be for different integers, we can use n for sequence A and x for sequence B)

Then we want to find:

aₙ = bₓ

where n and x are integer numbers.

Then we will heave:

3*n^2 - 1 = 30 - x^2

To find the pair, we could isolate one of the variables, then input different integers in the other variable and see if the outcome is also an integer.

Let's isolate n.

3*n^2 = 30 - x^2 + 1

3*n^2 = 31 - x^2

n^2 = (31 - x^2)/3

n = √(  (31 - x^2)/3)

Now let's input different values for x, and see if the outcome is also an integer, notice that x is in a negative term inside a square root, then we have only a few values of x such that the equation can be true.

Then let's start with x = 1.

n(1) = √(  (31 - 1^2)/3) = √(30/3) = √10

We know that √10 is not an integer.

now with x = 2,

n(2) = √(  (31 - 2^2)/3)  = √( (31 - 4)/3) = √(27/3) = √9 = 3

then if x = 2, we have n = 3.

Both of them are integers, then we get:

a₂ = 3*(3)^2 - 1 = 27 - 1 = 26

b₃ = 30 - 2^2 = 30 - 4 = 26

The number that belongs to both sequences is 26.

5 0
3 years ago
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