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inn [45]
3 years ago
10

Which expression represents the area of the triangle drawn below (4x-3) (2x-1) (4x-2) (3x-3)?

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

option C

Step-by-step explanation:

Area of the triangle=4x²+4x+1

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Vani signed up for a streaming music service that costs $12 per month. The service
ollegr [7]

Answer:

49.5 dollars first part and y=12+1.25x second part

Step-by-step explanation:

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3 years ago
If the number of people dying of heart disease in a city increases with the price of fuel, which of the following is the stronge
koban [17]
Its a correlation not a causality, therefore the answer is A
7 0
3 years ago
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Pablo simplified the expression (2 Superscript negative 4 Baseline) Superscript negative 2 as shown.
Lady_Fox [76]

Answer:

<h3>He should have found 8 as the exponent, not –8.</h3>

Step-by-step explanation:

Given the expression simplified by Pablo as (2^{-4})^{-2}

On simplification we have;

According to one of the law of indices (a^{m})^{n} = a^{mn}

Applying this law to the question will give;

(2^{-4})^{-2}\\=2^{-4*-2}  \\\= 2^{8}

Based on the calculation above, the exponent of 2 is 8 which means that Pablo should have found 8 as the exponent, not –8.

7 0
3 years ago
What is the radius of the circle defined by x2 + 2x + y2 + 6y − 39 = 0?<br> 49<br> 9<br> 7<br> 81
Bond [772]

radius = 7

the equation of a circle in standard form is

(x-a)² + (y-b)² = r²

where (a, b) are the coordinates of the centre and r is the radius

To obtain this form ' complete the square ' on both the x and y terms

x² + 2(1)x + 1 + y² + 2(3)y + 9  = 39 + 1 + 9

(x+1)² + (y+3)² = 49 ← in standard form

with centre (1, 3) and r = √49 = 7



7 0
3 years ago
Read 2 more answers
Suppose there are two lakes located on a stream. Clean water flows into the first lake, then the water from the first lake flows
never [62]

Answer:

a.  For the first lake;

c = (m·t - 0.005·m·t²)/100000

For the second tank, we have;

c = m·t/200 - m·t²/80000

b. t ≈ 1.00505 hours

c. 200 hours

Step-by-step explanation:

The flow rate of water in and out of the lakes = 500 liters/hour

The volume of water in the first lake = 100 thousand liters

The volume of water in the second lake = 200 thousand liters

The mass of toxic substances that entered into the first lake =  500 kg

The concentration of toxic substance in the first lake = m₁/(100000)

Therefore, we have;

The quantity of fresh water supplied at t hours = 500 × t

The change

The change in the mass of the toxic substance with time is given as follows

dm/dt = (m - m/100000 × 500 × t)/100000

c = (m·t - 0.005·m·t²)/100000

For the second tank, we have;

c = m/100000 × 500 × t - (m/100000 × 500 × t)/200000 × 500 × t

Using an online tool, we have;

c = m·t/200 - m·t²/80000

b. When c < 0.001 kg per liter, we have m < 0.001 × 100000, which gives m < 100

Substituting gives;

0.001 = (100·t - 0.005·100·t²)/100000, solving with an online tool, gives;

t ≈ 1.00505 hours

c. For maximum concentration, we have;

c = m·t/200 - m·t²/80000

m/200000 = m·t/200 - m·t²/80000

1/200000 = t/200 - t²/80000

dc/dt = d(t/200 - t²/80000)/dt = 0

Solving with an online tool gives t = 200 hours

6 0
3 years ago
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