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Dmitrij [34]
1 year ago
6

Help!! Express -0.4 as a fraction in simplest form.

Mathematics
1 answer:
charle [14.2K]1 year ago
6 0

\tt{Hey~there!

\tt{Let's~write~-0.4~as~a~fraction~in~simplest~form. \tt{In~order~to~do~that,~you~have~to~the~right~of~the~decimal~over~10.~Then,~you~have~to\tt{reduce.

\tt{-0.4\rightarrow\frac{-2}{5}

\boxed{\tt{\frac{-2}{5}}}

\tt{Hope~this~helps!

\boxed{\tt{-TestedHyperr}}

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100 points!!!!! STATISTICS PLEASE HELP SOON
Nikolay [14]

Answer:

Answer:

A) 98% Confidence interval for the proportion of all US buyers of this particular app who would have chosen Opinion B

= (0.51, 0.57)

This means that the true proportion of all thay would chose opinion B can take on values between the range of (0.51, 0.57)

B) For the confidence interval obtained to be valid, the conditions stated must be satisfied and for the sampling distribution to be approximately normal, the number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B must both be greater than 10.

Step-by-step explanation:

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion of all US buyers of this particular app who would have chosen Opinion B = 0.54

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 98% confidence interval for sample size of 1500 is obtained from the z-tables.

Critical value = 2.33

Standard error = σₓ = √[p(1-p)/n]

p = sample proportion = 0.54

n = sample size = 1500

σₓ = √(0.54×0.46/1500) = 0.0128685664 = 0.01287

98% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.54 ± (2.33 × 0.01287)

CI = 0.54 ± 0.02998)

98% CI = (0.51, 0.57)

98% Confidence interval = (0.51, 0.57)

B) The number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B are both greater than 10. Why must this inference condition be met?

For this confidence interval to be obtained using sample data, a couple of conditions are necessary to be satisfied. They include;

- The sample data must have been obtained using a random sampling technique.

- The sampling distribution must be normal or approximately normal.

- The variables of the sample data must be independent of each other.

On the second point, the condition for a binomial distribution to approximate a normal distribution is that

np ≥ 10

and n(1-p) ≥ 10

The quantity np is the actual sample mean which is the actual number of buyers that chose Opinion B while n(1-p) is the number of buyers that did not chose Opinion B.

For the confidence interval obtained to be valid, the conditions stated must be satisfied and for the sampling distribution to be approximately normal, the number of buyers that chose Opinion B and the number of buyers that did not choose Opinion B must both be greater than 10.

Hope this Helps!!!

8 0
1 year ago
Solve for x and y. And please explain
pishuonlain [190]
These are called same side interior angles.
They equal 180°.
1. 3x-7+4x-9=180
2. 7x-16=180
3. 7x=196
4. x=28
5 0
2 years ago
Write a sequence that has four geometric means between 31 and –23,540,625.
tino4ka555 [31]

Answer:

a_n=31(-15)^{n-1}

31, -465, 6975, -104,625, 1,569,375, -23,540,625

Step-by-step explanation:

The formula for a geometric sequence is:

a_n=a_1(r)^{n-1}

The formula for a geometric sequence is:

Where

r is the common ratio

a_1 is the first term

a_n is the nth term

In this case

a_1=31

a_6=-23,540,625

So:

-23,540,625=31(r)^{6-1}

Now we solve for r

-23,540,625=31(r)^{5}

-\frac{23,540,625}{31}=r^{5}\\\\r=\sqrt[5]{-\frac{23,540,625}{31}}\\\\r=-15

Then the four geometric means are

a_2=31(-15)^{2-1}=-465

a_3=31(-15)^{3-1}=6975

a_4=31(-15)^{4-1}=-104,625

a_5=31(-15)^{5-1}=1,569,375

31, -465, 6975, -104,625, 1,569,375, -23,540,625

7 0
2 years ago
Read 2 more answers
A square target is shown. A dart is dropped randomly onto the target. The dart is equally likely to hit any spot on the target.
Citrus2011 [14]

Answer:

b

Step-by-step explanation:

hope this helps

6 0
1 year ago
Read 2 more answers
The volume of a cube with side x is calculated by
Sphinxa [80]

Answer:

{x}^{3}

Step-by-step explanation:

volume \:  \:  \: of \:  \:  \: a \:  \: cube \\  = whl \\  = x \times x  \times x \\  =  {x}^{3}

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0
2 years ago
Read 2 more answers
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