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Anit [1.1K]
3 years ago
11

using the point-slope formula, what is the equation of the line that passes through the points (1, 5) and (0, 0)? a. y = x b. y

= 5x c. y = 5x 10 d. y = 5x – 1
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
First we find the slope m as follows:
m=\frac{y-y_{1}}{x-x_{1}}=\frac{5-0}{1-0}=5
So the equation is of the form:
y = 5x + b
When x = 1, y = 5. Therefore b = 0.
So the equation is:
y = 5x



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Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 =                                     => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq        => as (sinx)^2 + (cosx)^2 = 1

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Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb                      

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Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq     => (**) 2sinq*cosq =  sqin(2q)

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Hence

(sinq + cosq)^2  = 1 +  sin(2q)            => subtracting 1 from both sides

(sinq + cosq)^2  - 1 =   sin(2q)  

The last statement is what we are trying to prove.



Thank you,

MrB

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