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Soloha48 [4]
4 years ago
13

Julia studied math for 3 1/3 hours during the 4 days before her last math test. What was the average amount of time she studied

each day?
For this question I got 38.6 but that's really off.
Can someone tell me how I got this wrong in words?
Mathematics
1 answer:
brilliants [131]4 years ago
8 0

Answer:

answer 13.33333 hours h

Step-by-step explanation:

Julia studied 3 1/3 hours during 4 days

this means she studied:

3 1/3 of 4 days of 24 hours

3 1/3 = 9/3 x 1/3 = 10/3

and 4 days of 24 hours is 4 x 24 = 96

there for

10/3 x 96 = (10/1)x32 =320 hours

320/24 hours each day -13.3333


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dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

<u>1. 5 in and 1/3 in</u>

Here,

Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2

<u>2. 5 in and 4/3 in</u>

Here,

l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2

<u>3. 5/2 in and 4/3 in</u>

let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2

<u>4. 7/6 in and 6/7 in</u>

<u>Let</u>

l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2

<u>Hence,</u>

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

8 0
4 years ago
Please anyone help me with this please!!?​
Nataly [62]

Answer:

I think it's (-3, 1)

Hope this helps! :)

7 0
4 years ago
PLEASE HURRY write the equation of the inverse function y=1/2cos^-1(pix)-3
GaryK [48]

Answer:

f^{-1}(x) = \frac{cos(2x+6)}{\pi }

Step-by-step explanation:

y = \frac{1}{2} cos^{-1} (\pi x)-3

Firstly, we've to interchange the variables.

x = \frac{1}{2} cos^{-1}(\pi y)-3

Solving for y

x = \frac{cos^{-1} \pi y}{2} -3

Adding 3 to both sides

x+3 = \frac{cos^{-1}(\pi y)}{2}

Multiplying 2 to both sides

2(x+3) = cos^{-1} (\pi y)\\2x+6 = cos^{-1} (\pi y)

Taking cosine on both sides

\pi y = cos (2x+6)

Dividing both sides by y

y = \frac{cos(2x+6)}{\pi }

Replace y by f^{-1}(x)

=> f^{-1}(x) = \frac{cos(2x+6)}{\pi }

4 0
3 years ago
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Which data set could be represented by the box plot shown below? A horizontal boxplot is plotted along a horizontal axis marked
ludmilkaskok [199]

Answer:

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The box extends from 6 to 16 and is divided into 2 parts by a vertical line segment at 12. Therefore:

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The right whisker extends from 16 to 19, therefore the highest value is 19.

The set of data that satisfies these conditions where the numbers in bold are the 5- number summary is:

1,3,6,8,10,12,13,13,16,18,19

The correct option is B.

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3 years ago
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ANTONII [103]

dy%2Fdx+=+6x%5E2 So the slope at x = 2 is 6*(2^2) = 24
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