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Gnesinka [82]
3 years ago
14

A new car is purchased for 15700 dollars. The value of the car depreciates at 7.5% per year. To the nearest year, how long will

it be until the value of the car is 10100 dollars?
Mathematics
1 answer:
devlian [24]3 years ago
7 0

Answer:

10100=15700(1-0.075)^x

10100=15700(0.925)^x

divide both sides by 15700

0.925^x=101/157

convert decimal

(37/40)^x=101/157

take the log

x= log 37/40 (101/157)

x= 5.65824

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leonid [27]

The exponential function that represents the number of cells present at x hours is y = 100(2)ˣ

<h3>What is an exponential function?</h3>

An exponential function is in the form:

y = abˣ

Where a is the initial value and b is the multiplication factor.

Let y represent the number of cells after x hours.

From the table, at point (0, 100):

100 = ab⁰

a = 100

At point (1, 200):

200 = 100b

b = 2

The exponential function is y = 100(2)ˣ

Find out more on exponential function at: brainly.com/question/12940982

3 0
3 years ago
Raquel can type 63 words every minnute.Rick type then Raquel in 135 minute?Circle the letter of the correct answer.A 1350 B 4599
lozanna [386]

Answer: 1350

Step-by-step explanation:

Here is the correct question.

Raquel can type an average of 63 words per minute. Rick can type 73 words per minute. how many more words can Rick type than Raquel in 135 minutes? Jared chose B as the correct answer. How did he get that answer? Jared said the answer is 4599. How did he get that answer?

Rick's word per minute= 73

Raquel's word per minute= 63

Ricks word in 135minute= 73×135 = 9855

Raquel's word in 135 minutes=63×135 = 8505

=9855 - 8505

= 1350

Rick can type 1350 more words than Raquel in 135 minutes.

Jared's answer is wrong. He got the answer by multiplying 63 by 73 which gives 4599.

8 0
3 years ago
Read 2 more answers
At a certain high school, 15 students play stringed instruments and
Aleks [24]

Answer:

<em>0</em> is the probability that a  randomly selected student plays both a stringed and a brass  instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N(A \cup B)' = 5

<u>To find:</u>

The probability that a randomly selected students plays both = ?

<u>Solution:</u>

Total Number of students = N(A)+N(B)+N(A \cup B)' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

N(A\cap B) =0

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0

So, <em>0</em> is the probability that a  randomly selected student plays both a stringed and a brass  instrument.

5 0
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weeeeeb [17]

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