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2 years ago

14

A new car is purchased for 15700 dollars. The value of the car depreciates at 7.5% per year. To the nearest year, how long will

it be until the value of the car is 10100 dollars?

1 answer:

devlian [24]2 years ago

7 0

Answer:

10100=15700(1-0.075)^x

10100=15700(0.925)^x

divide both sides by 15700

0.925^x=101/157

convert decimal

(37/40)^x=101/157

take the log

x= log 37/40 (101/157)

x= 5.65824

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Amiraneli [1.4K]

Answer:

The roots of the equation are x=-3 and x=-2.5

Step-by-step explanation:

<u><em>The correct quadratic equation is</em></u>

2x^2+11x+15=0

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

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substitute in the formula

$x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}$

$x=\frac{-11(+/-)\sqrt{121-120}} {4}$

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2 years ago

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To find $(g \circ f)(x)$ , substitute f(x) for x in g(x) and simplify the expression.

Step 1 of 2

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Step 2 of 2

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