Note that 60 minutes is 1 standard deviation away from the mean and from recalling the 68-95-99.7 rule, the area that will remain is (100 - 68) = 32%. However, we only want the leftmost portion of this area, so the answer is 32%/2 = 16%.
<span>Choose D.</span>
Answer:
0.8743 = 87.43% probability that more than one accident occurs per year
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Buchtal, a manufacturer of ceramic tiles, reports on average 3.1 job-related accidents per year.
This means that
What is the probability that more than one accident occurs per year?
This is:
In which
Then
0.8743 = 87.43% probability that more than one accident occurs per year
The probability that the spinner will land on c at least once is 5/9
<h3>How to determine the probability?</h3>
From the complete question, the probability that the spinner will not land on c when spun twice is:
P = 4/9
Using the complement rule, the probability that the spinner will land on c at least once is:
P' = 1 - P
This gives
P' = 1 - 4/9
Evaluate
P' = 5/9
Hence, the probability that the spinner will land on c at least once is 5/9
Read more about probability at:
brainly.com/question/251701
#SPJ4
Answer:
S = 10
Step-by-step explanation:
Proportion is 2:1
HOPE THIS HELPS
PLZZ MARK BRAINLIEST
To find the z-score for a weight of 196 oz., use
A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.