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fredd [130]
2 years ago
5

Sarah has four friends. Lauren is 1.54m tall, Sophie is 1.50m tall, Kristy is 1.52m tall and Natalie is 1.49m tall. If they all

stood on top of eachother how high would theybe?
Mathematics
1 answer:
MaRussiya [10]2 years ago
5 0

Answer:

It would be 6.05m tall.

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What percentage of Priya's distance did Tyler walk​
Semmy [17]

Answer:

whats priya and tylers distance?

3 0
3 years ago
What is the solution to this inequality?
Ksivusya [100]
The answer is D. 

X/-5 = 2
x =2 * -5
Therefore, x is less than -10
4 0
3 years ago
Số táo của An, Bình, Chi là như nhau. An cho đi 17 quả , Chi cho đi 19 quả thì lúc này số táo của Chi gấp 5 lần tổng số táo còn
soldier1979 [14.2K]

Answer:

So, the initial number of apples is 7.

Step-by-step explanation:

The number of apples of An, Binh, and Chi are the same. An gave away 17 apples, Chi gave away 19 apples, so now Chi's apples are 5 times higher than the total remaining apples of An and Binh. How many apples did each of you have at first? (Solve the above problem by equation or system of equations)

Let the initial numbers of apples is a.

An gave 17 apples

Chi gave 19 apples

So,

x - 19 = 5 (x - 17 + x)

x - 19 = 5 (2x - 17)

x - 19 = 10 x - 85

9 x = 66

x = 7

6 0
3 years ago
A population of 50 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain up to 500 deer.
rewona [7]

Answer:

p1 = 70 deer

p2 = 98 deer

Step-by-step explanation:

We use the population growth expression:

N(t)=N_0\,(1+r)^t

which in our case renders:

N(t)=N_0\,(1+r)^t\\N(t)=50\,(1+0.4) ^t\\N(t)=50\,(1.4) ^t

Therefore, after 1 year the population would be:

N(1)=50\,(1.4) ^1=70

giving a total of 70 deer

and after two years, it would be:

N(2)=50\,(1.4) ^2=98

8 0
3 years ago
Please help on math.​
AleksAgata [21]

Answer:

3

Step-by-step explanation:

First set up your data in order

0,0,0,0,1,1,1,2,2,2,2,3,3

Second subtract the lowest to the highest which is 3-0=3

Hope this helps!

6 0
2 years ago
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