Question

If you were to use Lewis theory to predict the formula for the compound between rubidium and fluorine, it would most likely be:

Answer 1

Answer: The formula of the compound formed between rubidium and fluorine is RbF

Explanation:

Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Rubidium is the 37th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1$

This will loose 1 electron to form $Rb^+$ ion

Fluoride is the 9th element of the periodic table having electronic configuration of $1s^22s^22p^5$

This will gain 1 electron to form $F^-$ ion

To form $RbF$ compound, 1 rubidium ion is needed to neutralize the charge on fluoride ion

The formation of the given compounds is shown in the image below.