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vazorg [7]
2 years ago
11

Write complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead

(II) sulfate and aqueous potassium nitrate.
Chemistry
2 answers:
leva [86]2 years ago
8 0
The correct answer to this question is this one:

<span>Pb(N<span>O3</span><span>)2</span>(aq)+<span>K2</span>S<span>O4</span>(aq)→PbS<span>O4</span>(s)+2KN<span>O3</span>(aq)
</span>Everything except the lead sulfate is soluble, so they all dissociate.

<span>P<span>b<span>2+</span></span>+2N<span>O−3</span>+2<span>K+</span>+S<span>O<span>2−</span>4</span>→PbS<span>O4</span>(s)+2<span>K+</span>+2N<span>O−3
</span></span>Cancel out stuff that appears on both sides, and your net ionic equation is

<span>P<span>b<span>2+</span></span>(aq)+S<span>O<span>2−</span>4</span>(aq)→PbS<span>O4</span>(s)</span>
Semenov [28]2 years ago
8 0

Answer:

Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺ (aq) + SO₄²⁻ (aq) → PbSO₄(s) + 2K⁺ + 2 NO₃⁻ (aq)

Explanation:

1) Start understanding the nature of the reactants, the kind of reaction that occurs, and the nature of the products:

i) word equation (given):

aqueous lead(II) nitrate + aqueous potassium sulfate → solid lead(II) sulfate + aqueous potassium nitrate

ii) molecular equation, including the phases:

Pb(NO₃)₂ (aq) + K₂SO₄ (aq) → PbSO₄(s) + 2KNO₃ (aq)

iii) It is a combination of two salts to form two new salts, in a double replacement reaction.

2) Separate the ionic compounds in solution into its ions

i) Reactant side:

Pb(NO₃)₂ (aq) = Pb²⁺ (aq) + 2NO₃⁻ (aq)

K₂SO₄ (aq) = 2K⁺ (aq) + SO₄²⁻ (aq)

ii) Product side

PbSO₄(s) remains unchanged since it did not ionize

2KNO₃(aq) = 2K⁺ + 2 NO₃⁻ (aq)

3) Write both sides, i.e. the whole reaction in the ionic form:

Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺ (aq) + SO₄²⁻ (aq) → PbSO₄(s) + 2K⁺ + 2 NO₃⁻ (aq)

That is the total ionic equation.

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How many neutrons and protons are there in the nuclei of the following atoms. a. Li-7 b. O-16 c. Th-232 d. Pu-239
ANEK [815]

Answer:

a.

P = 3 , N = 4

b.

P = 8 , N = 8

c.

P = 90 , N = 142

d.

P = 94 , N = 145

Explanation:

Mass number  = Number of protons + Number of neutrons

Also,

Atomic number = Number of protons

<u>Li - 7</u>

Given, Mass number of Lithium = 7

For lithium, atomic number = 3

So,

Number of protons = 3

Number of neutrons = Mass number - Number of protons = 7 - 3 = 4

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Given, Mass number of oxygen = 16

For oxygen, atomic number = 8

So,

Number of protons = 8

Number of neutrons = Mass number - Number of protons = 16 - 8 = 8

<u>Th - 232</u>

Given, Mass number of Thorium = 232

For Thorium, atomic number = 90

So,

Number of protons = 90

Number of neutrons = Mass number - Number of protons = 232 - 90 = 142

<u>Pu - 239</u>

Given, Mass number of Plutonium = 239

For Plutonium, atomic number = 94

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Number of protons = 94

Number of neutrons = Mass number - Number of protons = 239 - 94 = 145

3 0
3 years ago
If 7.84 × 107 J of energy is released from a fusion reaction, what amount of mass in kilograms would be lost? Recall that c = 3
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3 0
3 years ago
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here is the answer to your question

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</span>
Here's the question.
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