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vazorg [7]
2 years ago
11

Write complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead

(II) sulfate and aqueous potassium nitrate.
Chemistry
2 answers:
leva [86]2 years ago
8 0
The correct answer to this question is this one:

<span>Pb(N<span>O3</span><span>)2</span>(aq)+<span>K2</span>S<span>O4</span>(aq)→PbS<span>O4</span>(s)+2KN<span>O3</span>(aq)
</span>Everything except the lead sulfate is soluble, so they all dissociate.

<span>P<span>b<span>2+</span></span>+2N<span>O−3</span>+2<span>K+</span>+S<span>O<span>2−</span>4</span>→PbS<span>O4</span>(s)+2<span>K+</span>+2N<span>O−3
</span></span>Cancel out stuff that appears on both sides, and your net ionic equation is

<span>P<span>b<span>2+</span></span>(aq)+S<span>O<span>2−</span>4</span>(aq)→PbS<span>O4</span>(s)</span>
Semenov [28]2 years ago
8 0

Answer:

Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺ (aq) + SO₄²⁻ (aq) → PbSO₄(s) + 2K⁺ + 2 NO₃⁻ (aq)

Explanation:

1) Start understanding the nature of the reactants, the kind of reaction that occurs, and the nature of the products:

i) word equation (given):

aqueous lead(II) nitrate + aqueous potassium sulfate → solid lead(II) sulfate + aqueous potassium nitrate

ii) molecular equation, including the phases:

Pb(NO₃)₂ (aq) + K₂SO₄ (aq) → PbSO₄(s) + 2KNO₃ (aq)

iii) It is a combination of two salts to form two new salts, in a double replacement reaction.

2) Separate the ionic compounds in solution into its ions

i) Reactant side:

Pb(NO₃)₂ (aq) = Pb²⁺ (aq) + 2NO₃⁻ (aq)

K₂SO₄ (aq) = 2K⁺ (aq) + SO₄²⁻ (aq)

ii) Product side

PbSO₄(s) remains unchanged since it did not ionize

2KNO₃(aq) = 2K⁺ + 2 NO₃⁻ (aq)

3) Write both sides, i.e. the whole reaction in the ionic form:

Pb²⁺ (aq) + 2NO₃⁻ (aq) + 2K⁺ (aq) + SO₄²⁻ (aq) → PbSO₄(s) + 2K⁺ + 2 NO₃⁻ (aq)

That is the total ionic equation.

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Answer:

\boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3}

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Explanation:

Formula:

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Substituting value of m & density in the formula:

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\frac{V1}{T1} = k

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The relation between volume, V of gas and Temperature, T of a gas is related by Charles Law.

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