Forgive me if this is wrong. I haven't done stat in a year, but comment if you need clarification!
Answer:
A
Step-by-step explanation:
So we have the equation:

First, let's subtract 16 from both sides:

Now, let's divide both sides by 3:

Remember that with fractional exponents, we can move the denominator into the root position. Therefore:
![(\sqrt[3]{x-4})^4=16](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx-4%7D%29%5E4%3D16)
Let's take the fourth root of both sides. Since we're taking an even root, make sure to have the plus-minus symbol!
![\sqrt[3]{x-4} =\pm 2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx-4%7D%20%3D%5Cpm%202)
Cube both sides. Since we're cubing, the plus-minus stays.

Add 4 to both sides.

Calculator:

So, our answer is A.
And we're done!
C(x) = 300.
Our question becomes simple: 300 = x^2-40x+610
x^2-40x+610-300 = 0
x^2-40x+310 = 0
Now find the value for x with either the quadratic formula or by factorization.
Let me know how it goes. Giving the full answer won’t help you improve
Answer:
if
is divided by
, the remainder is -9
Step-by-step explanation:
We need to find the remainder if
is divided by 
Dividing
by 
The division is shown in figure attached.
The remainder = -9
The quotient = x+3
So, if
is divided by
, the remainder is -9
Answer:
X is 6.
Step-by-step explanation:
What we know:
There's a ratio between 8 and 12, which simplifies to 2/3.
So, to find what x is, just multiply 2/3 times 9, to get 6 as x.