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ICE Princess25 [194]
3 years ago
6

7 times as many as 9 is

Mathematics
1 answer:
Charra [1.4K]3 years ago
3 0

Hi there! :)

<u><em>Answer:</em></u>

<u><em>=63</em></u>

<u><em>*The answer must have a positive sign.*</em></u>

Step-by-step explanation:

Product it's going to be multiply by the numbers, fractions, decimals, factors, and multiples.

First, you multiply by the numbers.

7*9=63

9*7=63

Then you can also divide by the numbers.

63/7=9

63/9=7

Final answer: → =63

63 times.

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D

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Hallie can use the equation p = 4l + 4w + 4h to determine the sum of the lengths of the edges of a rectangular prism. She begins
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The expression Hallie wrote is not clear, because if 0 is the only number that satisfies p = 4l + 4w + 4h = l + w + h.

But if you meant to write:

p = 4l + 4w + 4h

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then she could get something different.

Answer:

The expression (w + h) + p/4 should follow the subtraction if Hallie's equation is

p = 4l + 4w + 4h

p/4 = l + w + h

h = -

Step-by-step explanation:

Let us solve Hallie's problem.

She can use the equation:

p = 4l + 4w + 4h

to determine the sum of the lengths of the edges of a rectangular prism. Because she begin to solve the equation for h, let us solve for h.

This means we are trying to make h the subject of the formula.

p = 4l + 4w + 4h

When you factor out 4 on the right hand side, you have

p = 4(l + w + h)

Dividing both side by 4, we have

p/4 = l + w + h

Now, subtracting (l + w) from both sides, we have

p/4 - (l + w) = h.

This can be written as:

h = - (l + w) + p/4

And that is what Hallie wanted to obtain.

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Which sums are equal to 1hold 6/8?
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Step-by-step explanation:

Given f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y

a)

we know that \int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1

therefore \int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1

on integrating we get

c=(1/6640)

b)

P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

on doing the integration we get

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c)

marginal density of X is

f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx

on doing integration we get

f(y)=\frac{(y+40.5)}{83}

d)

P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

solve the above integration we get the answer

e)

P(X>20, 0

solve the above integration we get the answer

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we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

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