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damaskus [11]
3 years ago
13

Find the volume of a cone that is 17.3ft and 4.7ft

Mathematics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:81.31

Step-by-step explanation:

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Reduce the fraction to lowest terms m^2/m^2-n^2
Softa [21]

Answer:

\boxed{\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}}

Step-by-step explanation:

Factor \bold{m^2-n^2}

\bold{\left(m+n\right)\left(m-n\right)}

Rewrite Equation

\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}

4 0
3 years ago
Read 2 more answers
Find expressions for the partial derivatives of the following functions:
nlexa [21]

Answer:

Step-by-step explanation: partial derivative is the differentiation of one variable e.g. X while leaving the values of the other variable e.g. Y

These four questions A, B, C and D have different functions separated by commas. I will not assume the commas to be something else like a plus sign.

A. f(x) = g'(x).k(y) , g'(x) + h(y)

f(y) = k'(y).g(x) , g(x) + h'(y)

B. f(x) = g'x (x+y)

f(y) = g'y (x+y) , h'y (y+z)

f(z) = h'z (y+z)

C. f(x) = f'x (xy) , f'x (zx)

f(y) = f'y (xy) , f'y (yz)

f(z) = f'z (yz) , f'z (zx)

D. f(x) = f'x (x) , g'(x) , h'x (x,y)

f(y) = h'x (x,y)

These are the partial derivative expressions for each variable in each function. You will need to pay a lot of attention to understand:

* while differentiating X alone, functions in Y which are separated by commas from the functions in X, are ignored totally because they are different questions

* In functions where X added to Y is in a bracket e.g. (x+y), to find the derivative of X, Y isn't thrown away because they are joined (by a plus sign) the derivative of X alone in this case would be f'x (x+y)

* f(x), just like g(x), simply means/represents a function in X hence f'(x) means the differentiation of all X-terms in that function

6 0
3 years ago
I need these questions to be answered correctly plz tryna get my grade up
Reil [10]

Answer:

1. 81

2. 4 (square root of) 25^3

3. 30 (square root of) 10

6 0
3 years ago
Which expressions are equivalent to -2(5x-1)+7(5x-1)-3(-5x+1)
blondinia [14]

Answer:

x=1/5

Step-by-step explanation:

To solve this question we will have to open the bracket first

So let's go back to the given question

-2(5x-1)+7(5x-1)-3(-5x+1)

We can actually equate the equation to zero

Let's solve

-10x+2+35x-7+15x-3=0

Let's collect like terms

-10x+35x+15x=-2+7+3

40x=8

Let's make x the subject of formula by dividing both sides by 40

x=1/5

So the final answer is 1/5

8 0
3 years ago
Linda goes water-skiing one sunny afternoon. After skiing for 15 min, she signals to the driver of the boat to take her back to
trasher [3.6K]
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2


abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.


d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
4 0
3 years ago
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