Y< X^-X-6
1. Solve the x first by factor.
2. X equals to (x-3)(x+2). X=3 or -2.
3. Looking at the problem, we see two similar answers with 3 and -2.
4. The correct answer is D, y=0. Because 0 is less than 3, choice A fails because y is greater than x.
The next step Juan will take is to multiply the second fraction by (x-2)/(x-2).
Given that Juan needs to rewrite this difference as one expression (3x/(x²-7x+10))-(2x/(3x-15)) and factor the denominator as (3x/(x-2)(x-5))-(2x/3(x-5)).
An algebraic expression in mathematics is an expression composed of variables and constants and algebraic operations (addition, subtraction, etc.). Expressions are made up of concepts.
The given expression is (3x/(x²-7x+10))-(2x/(3x-15))
Firstly, we will factored the denominator as
(3x/(x-2)(x-5))-(2x/3(x-5)).
Now, we will multiply and divide the second fraction by (x-2), we get
(3x/(x-2)(x-5))-((2x(x-2))/3(x-5)(x-2)).
Hence, the next step when subtracting these expressions (3x/(x-2)(x-5))-(2x/3(x-5)) is multiply the second fraction by (x-2)/(x-2).
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Answer:
p = 250 - 15(w)
Step-by-step explanation:
Original amount: 250
No of weeks to return money: w
Amount to pay each week: 15
Amount that he has paid back: 15 × w (When we subtract this term from the total we will get the answer)
So after w weeks he owes his parents :
p = 250 - 15(w)
Answer:m>1
Step-by-step explanation:
You add 3 to both sides because you minusing the 3. Then since your working with a negative you have to switch the signs
Answer:
13/30
Step-by-step explanation:
Add: -1/
3
+ 2/
5
= -1 · 5/
3 · 5
+ 2 · 3/
5 · 3
= -5/
15
+ 6/
15
= -5 + 6/
15
= 1/
15
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of the both denominators - LCM(3, 5) = 15. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 3 × 5 = 15. In the next intermediate step the fraction result cannot be further simplified by canceling.
In words - minus one third plus two fifths = one fifteenth.
Subtract: 1/
2
- the result of step No. 1 = 1/
2
- 1/
15
= 1 · 15/
2 · 15
- 1 · 2/
15 · 2
= 15/
30
- 2/
30
= 15 - 2/
30
= 13/
30
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of the both denominators - LCM(2, 15) = 30. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 2 × 15 = 30. In the next intermediate step the fraction result cannot be further simplified by canceling.
In words - one half minus one fifteenth = thirteen thirtieths.
