4 years ago

Compute the probability of random sly selecting a queen or diamond.

Mathematics

1 answer:

FrozenT [24]4 years ago

3 0

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Three phones in a shipment of eighteen are known to be broken. A randomly selected phone is removed from the shipment and tested

statuscvo [17]

Answer:

$\frac{14}{17}$

Step-by-step explanation:

Number of phones broken = 3

Number of phones not broken = 15

Total number of phone in the shipment = 18

Since a not broken phone has been randomly selected, the number of phones not broken reduces to 14. And the total number of phones would be 17.

Pr(of newly selected phone NOT broken) = $\frac{number of not broken phones}{total number of phones}$

= $\frac{14}{17}$

Therefore, the probability of the selected phone not being broken is $\frac{14}{17}$ .

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3 years ago

Angles U and V are supplementary angles. The ratio of their measures is 7:13. Find the measure of each angle

Advocard [28]

Supplementary=add to 180. U/V=7/13, U+V=180. Solving, U=63 and V=117

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3 years ago

9 (y+2) -5 (y-6) = -4y -9 solve for y

nydimaria [60]

$9y+18-5y+30=-4y-9 \\8y+57=0 \\y=-\frac{57}{8}=-7.125 \\$

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4 years ago

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