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Mashcka [7]
2 years ago
8

Are 25 milligrams lighter or heavier than 25 centigrams

Mathematics
2 answers:
masya89 [10]2 years ago
8 0

Answer:

<em>25 mg. is lighter than 25 cg.</em>

<em />

Step-by-step explanation:

<em>Well,</em>

<em />

<em>The prefix "milli" means thousandth and the prefix "centi" means hundredth.  So a milligram will be one-tenth of a centigram.</em>

<em />

<em>10 mg. = 1 cg.</em>

<em>25 mg. = 2.5 cg.</em>

<em />

<em>2.5 cg. < 25 cg.</em>

<em />

<em>25 mg. is lighter than 25 cg.</em>

Zielflug [23.3K]2 years ago
3 0

Answer:

25 milligrams are lighter, because 1 milligram equivales to 1 gram multiplied by 100.

Step-by-step explanation:

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Step-by-step explanation:

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8 0
2 years ago
A low P-Value in ANOVA table mean that the population mean of each treatment effects are different. the population mean of at le
Verizon [17]

Answer:

The population mean of at least one treatment effect are different.

Step-by-step explanation:

An analysis of variance (ANOVA) is conducted in order to determine if there are significant differences between the values of the population mean with respect to the response variable for the domains that under the effects of different treatments. A low p-value leads to reject the null hypothesis of the following hypothesis system:

H_0: \mu_1=\mu_2=...=\mu_k\\\\\\H_a: \mu_i \neq\mu_j, for $ for some i, j between 1 and k.$

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4 0
3 years ago
Choose one of the factors of x^3 + 343.
Debora [2.8K]

First, note that 343=7^3. Then use the formula for the sum of perfect cubes:

a^3+b^3=(a+b)(a^2-ab+b^2).

Therefore,

x^3 + 343=x^3+7^3=(x+7)(x^2-7x+49).

The quadratic trinomial x^2-7x+49 couldn't be factored anymore, so the expression x^3 + 343 has two factors x+7 and x^2-7x+49.

Answer: correct choice is A.

3 0
3 years ago
Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili
pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0
1 year ago
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