You go it right it's the first one
Since we already know that the older child is a girl (a 100% chance to be a girl), there must be a 50% chance that the other child is a girl. Therefore, the probability that both children are girls is 50%.
Hope this helps!
Answer:
4
Step-by-step explanation:
ΔABC is congruent with ΔDEF. That means the corresponding sides are congruent.
Look at the order of the letters. EF are the last two letters of ΔDEF. So this corresponds with the last two letters of ΔABC. Therefore, EF ≅ BC.
EF ≅ BC
x² + 8x = 48
x² + 8x − 48 = 0
(x + 12) (x − 4) = 0
x = -12 or 4
Since x can't be negative, x = 4.
To solve for the confidence interval for the population
mean mu, we can use the formula:
Confidence interval = x ± z * s / sqrt (n)
where x is the sample mean, s is the standard deviation,
and n is the sample size
At 95% confidence level, the value of z is equivalent to:
z = 1.96
Therefore substituting the given values into the
equation:
Confidence interval = 3 ± 1.96 * 5.8 / sqrt (51)
Confidence interval = 3 ± 1.59
Confidence interval = 1.41, 4.59
Therefore the population mean mu has an approximate range
or confidence interval from 1.41 kg to 4.59 kg.
A. √(0.8^2) + (0.6^2) = √1 = 1 => OK
<span>b.(-2/3,√ 5/3) = √(-2/3)^2 + 5/9) = √(4/9 +5/9) = √1 = 1 => OK
c.(√ 3/2, 1/3) = √(3/4 + 1/9) < 1 => it is inside the unit circle
d.(1,1)
= √(1 + 1) = √2 > 1 => NO. This point is beyond the limits of the unit circle.</span>
