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a_sh-v [17]
3 years ago
11

A father and a son were driving they had a car crash accident and the father died, the ambulance took the boy to the hospital bu

t the surgeon said I can’t operate on him because he is my son
Who is the surgeon
Mathematics
2 answers:
Arada [10]3 years ago
8 0

Who says the mother can’t be the surgeon?

VashaNatasha [74]3 years ago
4 0

Answer:

The surgeon is the mother of the boy because of the fact that the father was in the car crash with him and died, therefore this is the only other logical option.

You might be interested in
Whats is the diference of:
grandymaker [24]

Answer:

2h^2

Step-by-step explanation:

=> (10h^4+h^2)-(10h^4-h^2)

=> 10h^4+h^2-10h^4+h^2

=> h^2+h^2

=> 2h^2

7 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
Do these side lengths make a triangle? <br> 8, 8, 4,
jeyben [28]

Answer: weird question but yes they should if there is only 3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Disruptive properties<br> 5(4 + 7x)
Gnesinka [82]

Answer:

It is 35x+20

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need help with with problem please thanks!
liraira [26]
40 is the correct answer. Hope this helps :)
5 0
3 years ago
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