Analog signals require more energy.
Analog=Constant flowing modulated
Digital is bursts of on/off binary data.
Answer:
The answer is "False"
Explanation:
It is put to use Six Sigma had 3.4 defects per million opportunities (DPMO) from the start, allowing for a 1.5-sigma process shift. However, the definition of zero faults is a little hazy. Perhaps the area beyond 3.4 DPMO is referred to by the term "zero faults.", that's why Before being released, large computer programs, such as operating systems, must have no faults the wrong choice.
Answer:
Variable, operator, expression, value.
Explanation:
We could use variables, operators, expressions, and values in a mathematical formula, we're going to do an example with every part.
For this example we're going to use a simple sum formula:
First, we have 3 variables:
sum;
sum1;
sum2;
Second, we have 3 operators:
=, + and *
Third, we have our expression and 1 value:
sum = sum1 + (sum2 * 5);
(sum2 * 5) = expression;
5 = value;
We're going to see the result when we print the variable sum.
Look at the serial number. Find the sticker on the back of your PS3. The last digits will inform you as to whether you have full hardware backwards compatibility, or limited software emulation:
CECHAxx (60 GB) and CECHBxx (20 GB) - Full hardware backwards compatibility.
CECHCxx (60 GB) and CECHExx (80 GB) - Limited hardware emulation (These models do not contain the Emotion Engine, as it is instead emulated by the Cell processor). You may run into issues with some PS2 discs.
CECHGxx and above - These models are not backwards compatible.
Answer:
This code will print: 4
Explanation:
Following is the step-by-step explanation for the given code:
- Given is the array of data type double named myList, it has entries, 1, 5, 5, 5,5, 1:
double[] myList = {1, 5, 5, 5, 5, 1};
- Now the first element of the array (1) with index 0 will be stored in the variable max (data type double).
double max = myList[0];
- A variable indexOfMax having datatype int will be initiated as 0.
int indexOfMax = 0;
- Now for loop will be used to find the maximum number of the array. The variable i will be put as index for each element to compare with first element. If the checked element is greater than or equal to the integer in max, it will be replaced. So at the end the variable max will have value 5 that will be at index i = 4.
for (int i = 1; i < myList.length; i++)
{ if (myList[i] >= max)
{ max = myList[i];
- Now the variable i that is the index for max value will be stored in the variable indexOfMax (indexOfMax = 4).
indexOfMax = i; }}
- At end the value stored in variable indexOfMax will be printed, so 4 will be printed as output.
System.out.println(indexOfMax);
i hope it will help you!
