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3 years ago

PLEASE HELP ASAP!!!!

Mathematics

1 answer:

frez [133]3 years ago

7 0

To find the probability that both of the events occur, we simply multiply them!

4/5 × 1/7 = 4/35

The probability that both the pirate and the Captain hit each other's ships at the same time is 4/35 or about 11.4%

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What is the value of x in the equation 5x+3=4x?

Volgvan

Answer:

x = -3

Step-by-step explanation:

5x + 3 = 4x,

x + 3 = 0,

x = -3

3 0

3 years ago

Read 2 more answers

Harold earns $10.50 per hour working at a doctor’s office. On Monday he spent 1 5/12 hours filing paper work, 1 3/4 sending emai

maks197457 [2]

Answer:$57.75

Step-by-step explanation:

Find the total amount of hours he worked

$1\frac{5}{12} +1\frac{3}{4} +2\frac{1}{3}\\\\\frac{17}{12}+ \frac{7}{4} +\frac{7}{3} \\\\\frac{17+21+28}{12} \\\\\frac{66}{12}=\frac{66/2}{12/2}=\frac{33/3}{6/3}= \frac{11}{2} or 5\frac{1}{2} or 5.5h$

So, he worked 5.5h and he earns $10.50 an hour.

($10.50)(5.5h)=$57.75

5 0

3 years ago

Round the answer to the nearest

kykrilka [37]

By knowing the blood pressure and applying the quadratic formula, the age of a man whose normal blood pressure is 129 mm Hg is 40 years old.

<h3>How to use quadratic equations to determine the age of a man in terms of blood pressure</h3>

In this problem we have a quadratic function that models the blood pressure as a function of age. As the latter is known, we must use the quadratic formula to determine the former:

129 = 0.006 · A² - 0.02 ·A + 120

0.006 · A² - 0.02 · A - 9 = 0

$A = \frac{0.02 \pm \sqrt{0.006^{2}-4\cdot (0.006)\cdot (- 9)}}{2\cdot (0.006)}$

A = 1.667 + 38.733

A = 40

By knowing the blood pressure and applying the quadratic formula, the age of a man whose normal blood pressure is 129 mm Hg is 40 years old.

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

4 0

1 year ago

Heights in inches of several tomato plants : 16,18,18,20,17,10,18,17 mean absolute deviation :

AysviL [449]

18 would have to be the mean because of the average

7 0

3 years ago

If f(x) = 5-2x^3 and f^-1 denotes the inverse function of f, then f^-1(x)= ?

-BARSIC- [3]

$f(x)=5-2x^3\\
y=5-2x^3\\
2x^3=-y+5\\
x^3=-\dfrac{y-5}{2}\\
x=\sqrt[3]{-\dfrac{y-5}{2}}=-\sqrt[3]{\dfrac{y-5}{2}}\\
f^{-1}(x)=-\sqrt[3]{\dfrac{x-5}{2}}$

7 0

3 years ago